Answer:
def sum_digits(number):
total = 0
if 1 <= number <= 999:
while number > 0:
r = int (number % 10)
total +=r
number /= 10
else:
return -1
return total
print(sum_digits(658))
Explanation:
Write a function named sum_digits that takes one parameter, number
Check if the number is between 1 and 999. If it is, create a while loop that iterates until number is greater than 0. Get the last digit of the number using mudulo and add it to the total. Then, divide the number by 10 to move to the next digit. This process will continue until the number is equal to 0.
If the number is not in the given range, return -1, indicating invalid range.
Call the function and print the result
It gains purchasing power. Less money in circulation = more value.
Answer:
When a programmer tries to access an item in an array cell whose index is greater than or equal to the array's logical size, this data element or item is garbage. This means that currently, the item is not the part of the program's useful data. Garbage contains objects or data which will not be used by a program running on it. So the value returned could be either of the two:
- Value would be an arbitrary or random number if it is an array of numbers. Arbitrary means that the value is not predefined or specified in advance.
- Value returned would be null if it is an array of objects.
Answer:
c) it will always return with an answer of 7 or fewer comparisons of data.
Explanation:
As maximum number of comparison in worst case for sorted binary search is log₂n, here n = 100, so maximum search is at least 6.6 which is approximately 7.
Answer:
Determine if the software or service is authorized
Explanation:
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