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3 years ago

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What is the area of the trapezoid with height 10 units?

2 answers:

Ainat [17]3 years ago

5 0

Ya but I think its like 40 hope this helps

harina [27]3 years ago

4 0

Use Formula A=1/2h(b1+b2)

Question 1

What is the area of this trapezoid?

Questions 2

What is the area of the trapezoid with height 10 units?

Question 3

What is the area of this trapezoid?

Question 4

The figure shows the front side of a metal desk in the shape of a trapezoid. What is the area of this trapezoid?

Question 5

Duc has a trapezoid shaped section of his yard fenced off for his pets. The lengths of the parallel sides of the trapezoid are 8 ft and 14 ft. The height of the trapezoid section is 4 ft.

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A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h

mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere $=\frac{2}{3}\pi r^3$

Volume of a Cylinder $=\pi r^2 h$

Therefore:

The Volume of the Solid formed

$=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Area of the Hemisphere = $2\pi r^2$

Curved Surface Area of the Cylinder = $2\pi rh$

Total Surface Area=

$2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh$

Cost of the Hemispherical Ends = 2 X Cost of the surface area of the sides.

Therefore total Cost, C

$=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh$

Recall: $h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Therefore:

$C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}$

The minimum cost occurs at the point where the derivative equals zero.

$C^{'}=\frac{-27840+32\pi r^3}{3r^2}$

$When \:C^{'}=0$

$-27840+32\pi r^3=0\\27840=32\pi r^3\\r^3=27840 \div 32\pi=276.9296\\r=\sqrt[3]{276.9296} =6.518$

Recall:

$h=\frac{4640}{\pi r^2}-\frac{4r}{3}\\h=\frac{4640}{\pi*6.518^2}-\frac{4*6.518}{3}\\h=26.074 feet$

Therefore, the dimensions that will minimize the cost are:

Radius =6.518 feet

Height = 26.074 feet

5 0

3 years ago

Write the equation for the line whose slope is -1/4 and goes through the point (-2,6)

Kryger [21]

Answer:

$y = -\frac{1}{4} + \frac{11}{2}$

Step-by-step explanation:

use y = mx + b where:

y = y-coordinate = 6

m = slope = -1/4

x = x-coordinate = -2

b = y-intercept = what we're solving for to complete the equation

plug the values into the equation

$6 = -\frac{1}{4}(-2) + b$ multiply $-\frac{1}{4}$ and 2

$6 = \frac{1}{2} + b$ subtract $\frac{1}{2}$ from both sides

$b = \frac{11}{2}$

now we plug m and b into the equation and leave x and y as variables to get the final equation:

$y = -\frac{1}{4} + \frac{11}{2}$

8 0

3 years ago

Which best compares the pair of intersecting rays with the angle

madam [21]

Answer:

C)The rays extend infinitely, and the angle is made by rays which have a common endpoint

Step-by-step explanation:

A ray is a line segment having one end point while extending in the other/opposite direction

An angle is made by two lines(rays) with common end point (vertex)

So when an angle is formed by the pair of intersecting rays the following options are ruled out

A) rays cannot have two end points

B) As rays extends infinitely in one direction, so having number of points is wrong

D)angles do not have lines

the following is best explanation is C

The rays extend infinitely, and the angle is made by rays which have a common endpoint !

5 0

3 years ago

It’s the end of the accounting period, and no electric bill has been received (but the expense has been incurred); you should re

san4es73 [151]

<span>C. increases the total liabilities and increases the total expenses. </span>

4 0

3 years ago

Read 2 more answers

Find the dy/dx for the equation below using implicit differentiation.

n200080 [17]

First of all, recall that y is a product of function of x. We have three factors:

$f(x)=x^2,\quad g(x)=e^{3x},\quad h(x)=\sin(4x)$

The derivative of a product of function is computed by deriving one function at the time, and then adding all the results:

$y' = f'(x)g(x)h(x)+f(x)g'(x)h(x)+f(x)g(x)h'(x)$

Let's compute the derivative of each function first:

$f'(x)=2x,\quad g'(x) = 3e^{3x},\quad h'(x)=4\cos(4x)$

Now plug f, f', g, g', h, h' in the formula above as required:

$2xe^{3x}\sin(4x)+3x^2e^{3x}\sin(4x)+4x^2e^{3x}\cos(4x)$

6 0

3 years ago