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Naddika [18.5K]
3 years ago
14

WILL GIVE BRAINLIEST! (Only for the first CORRECT Answer, though)

Mathematics
2 answers:
grandymaker [24]3 years ago
7 0

Answer: plane b because it was 9.73 miles away

Step-by-step explanation:

Rzqust [24]3 years ago
4 0

Answer:

Plane A will be farther because it is flying at a lower angle so it will be able to cover more ground by flying slightly more forwards than going more upwards like plane B

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- Pressure
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Jeremy drove 812 miles on 24.3 gallons of gas. what was his gas mileage, rounded to the nearest mpg?
yuradex [85]
The answer is D because you have to divide 812 by 25.3
5 0
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Write the quotient as a power
elena55 [62]

Answer:

10^3

Step-by-step explanation:

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7 0
3 years ago
A pole 5 feet tall is used to support a guy wire for a tower, which runs from the tower to a metal stake in the ground. After pl
sammy [17]

The length of the guy's wire to the nearest foot is 89 feet.

The situation forms a right-angled triangle.

<h3>Properties of a right angle triangle:</h3>
  • A right-angle triangle has one angle of 90 degrees.
  • The sides can be found using the Pythagoras theorem.
  • The angles can be found using trigonometric ratios.

The hypotenuse of the triangle is the length of the wire.

let's use the smaller triangle to find the angle opposite the tower. Therefore,

tan ∅ = opposite / adjacent

tan ∅ =  5 / 2

∅ = tan⁻¹ 2.5

∅ = 68.1985905136

∅ = 68.20°

Therefore,

cos 68.20 = adjacent / hypotenuse

cos 68.20 = 33 / hypotenuse

hypotenuse = 33 / cos 68.20

hypotenuse = 88.8606843161

Therefore,

length of wire ≈ 89 feet.

learn more on triangles here; brainly.com/question/25762788?referrer=searchResults

4 0
2 years ago
Find a particular solution to y" - y + y = 2 sin(3x)
leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

     =e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}

Multiplying both sides of equation (1) by integrating factor and integrating we get

\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I

I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx

8 0
3 years ago
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