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2 years ago

Which of the following increases at the fastest rate for larger values of x?

Mathematics

2 answers:

kondor19780726 [428]2 years ago

7 0

Answer:

Option d

d) f(x)=6x^3+1

Step-by-step explanation:

Given data

a) f(x)=6^x+1

b) f(x)=6x^2+1

c) f(x)=6x+1

d) f(x)=6x^3+1

In all option d is the function that increases at the fastest rate, this is because the power of x is the highest

charle [14.2K]2 years ago

5 0

Answer:

Option d

d) f(x)=6x^3+1

Step-by-step explanation:

Given data

a) f(x)=6^x+1

b) f(x)=6x^2+1

c) f(x)=6x+1

d) f(x)=6x^3+1

In all option d is the function that increases at the fastest rate, this is because the power of x is the highest

Step-by-step explanation:

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Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

3 years ago

The equation is________<br> Solve the equation x=________

Komok [63]

Answer:

7x-5 = 9

x = 2

Step-by-step explanation:

Let x be the number

7x-5 = 9

Add 5 to each side

7x-5+5 = 9+5

Divide each side by 7

7x = 14

7x/7 = 14/7

x=2

5 0

3 years ago

A prism is completely filled with 96 cubes that have edge length of 1/2 cm.

ch4aika [34]

I know this is kinda late, but...

You can solve this easily as long as you remember how to find the volume of a cube. v=a^3, when a means length. The length is 1/2 cm, or .5 cm.
So, v+.5^3, which equals .125 cm. Each cube has a that volume. Now, multiply that by how many actual cubes there are, 96.

96 * .125 = 12

8 0

2 years ago

Read 2 more answers

Choice the correct answer

PSYCHO15rus [73]

Answer:

wheres A

Step-by-step explanation:

8 0

2 years ago

Robin can run 1.71 kilometers in 10 minutes. How far can she run in 1.5 hours?

Flura [38]

Answer:

I think is 15.39 kilometers

Step-by-step explanation:

1 hour=60 minutes +.5 hours =90 minutes = 9 x 1.71 = 15.39

7 0

2 years ago