Question

What is the following sum 5x(^3sqrt(x^2y)+2(^3sqrtx^5y)

Answer 1

Answer:

7x[∛x^2y]

Step-by-step explanation:

given:

$5x\sqrt[3]{x^2y} +2\sqrt[3]{x^5y} \\5x(x^\frac{2}{3}.y^\frac{1}{3}) + 2.x^\frac{5}{3}.y^\frac{1}{3} \\5x.x^\frac{2}{3}.y^\frac{1}{3} + 2.x^\frac{5}{3}.y^\frac{1}{3} \\5x^\frac{5}{3}.y^\frac{1}{3} + 2.x^\frac{5}{3}.y^\frac{1}{3} \\\\ y^\frac{1}{3} (5x^\frac{5}{3} + 2x^\frac{5}{3} )\\y^\frac{1}{3} (7x^\frac{5}{3}} )\\7\sqrt[3]{x^5y}\\ 7x\sqrt[3]{x^2y}$ !

Answer 2

Answer:

 [/tex]7x\sqrt[3]{x^2y}[/tex]

Step-by-step explanation:

The given equation is:

$5x\sqrt[3]{x^2y} +2\sqrt{3}{x^5y}$

Solving this equation step by step

$5x\sqrt[3]{x^2y} +2\sqrt{3}{x^5y}$

∵ x⁵ = x³ × x²

$5x\sqrt[3]{x^2y} +2\sqrt[3]{(x^3\times x^2)y}$

take the x³ outside the cube root in second term

$5x\sqrt[3]{x^2y} +2x\sqrt[3]{(x^2)y}\\\sqrt[3]{x^2y} (5x+2x)\\7x\sqrt[3]{x^2y}$

Thus, last option is correct.