What is the answer to all the q's ******WILL GIVE BRAINLIST******
2 answers:
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The roots of an equation are simply the x-intercepts of the equation.
See below for the proof that has at least two real roots
The equation is given as:
There are several ways to show that an equation has real roots, one of these ways is by using graphs.
See attachment for the graph of
Next, we count the x-intercepts of the graph (i.e. the points where the equation crosses the x-axis)
From the attached graph, we can see that crosses the x-axis at approximately <em>-2000 and 2000 </em>between the domain -2500 and 2500
This means that has at least two real roots
Read more about roots of an equation at:
Answer:
(-3/2, 6)
Step-by-step explanation:
(-3,8) (6,-4)
As we move along the line segment with endpoints (-3,8) and (6,-4) from (-3,8) to (6,-4) x increases by 9 units (from -3 to 6) and y decreases by -12 units (from 8 to -4).
for ratio of 1:5
Since 1+5=6, the point we are looking for is 1/6 of the way from (-3,8) to (6,-4).
So, the desired point is
(-3 + (1/6)(9), 8 - (1/6)(12) )
= (-3 + 3/2 , 8 - 2)
= ( (-6 + 3)/2, 6)
= (-3/2, 6)
for map reference see the image below
