Using the following image, find GH given HI=1 and GH=6.
1 answer:
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Answer:
The surface area of the right regular hexagonal pyramid is 50.78 cm².
Step-by-step explanation:
Given:
A right regular hexagonal pyramid with sides(s) 2 cm and slant height(h) 5 cm.
Now, to find the surface area(SA) of the right regular hexagonal pyramid.
So, we find the area of the base(b) first:
Area of the base =
=
On solving we get:
Area of the base(b) =
Then, we find the perimeter(p) :
Perimeter = s × 6
Now, putting the formula for getting the surface area:
Surface area = perimeter × height/2 + Area of the base.
As, <em>the surface area is 50.784 and rounding to nearest hundredth becomes 50.78 because in hundredth place it is 8 and in thousandth place it is 4 so rounding to it become 50.78.</em>
Therefore, the surface area of the right regular hexagonal pyramid is 50.78 cm².