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MrMuchimi
3 years ago
7

One morning, Justin drove 5 hours before stopping to eat lunch at chick-fil-A. After lunch, he increased his speedy by 10 mph. I

f he completed 310-mile trip in 9 hours of driving time, how fast did he drive in the morning?
Mathematics
1 answer:
LuckyWell [14K]3 years ago
7 0

Answer:

30 mph

Step-by-step explanation:

Let the morning speed be represented by s.

Then the total distance drivern is 310 mi and this is equal to

5s + 4(s + 10):

5s + 4s + 40 = 310, or

    9s             = 270

Solving for s, we get s = 270/9 = 30

Then s + 10 = 40

He drove 30 mph in the morning and 40 mph in the afternoon.

Check:  (30 mph)(5 hrs) + (40 mph)(4 hrs) =  310 miles.  CORRECT

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5 0
2 years ago
Which rational number is one tick mark to the right of Negative 6 Over 4 on the number line below?
murzikaleks [220]

Answer:

The number line is missing, but as we are know that the number marked in the number line is -6/4, i will guess that the ticks are spearated by fourts (the distance between each tick is 1/4).

Now, for the number at the right of -6/4, we should add the distance for one tick, this means that the number at the right is:

-6/4 + 1/4 = -5/4.

Now i will give some other examples:

Now, if the distance between ticks is 2/4, then the number at the right will be:

-6/4 + 2/4 = -4/4 = -1

Now, if the distance between ticks is 3/4, the the number at the right will be:

-6/4 + 3/4 = -3/4.

4 0
3 years ago
For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). If T is the sum of
Katena32 [7]

Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is (-1)^{k+1}(\frac{1}{2^{k}}).

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as (-1)^{k+1}(\frac{1}{2^{k}}).

where k is from 1 to 10.

By the given expression sequence will be \frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......

In this sequence first term "a" = \frac{1}{2}

and common ratio in each successive term to the previous term is 'r' = \frac{\frac{(-1)}{4}}{\frac{1}{2} }

r = -\frac{1}{2}

Since the sequence is infinite and the formula to calculate the sum is represented by

S=\frac{a}{1-r} [Here r is less than 1]

S=\frac{\frac{1}{2} }{1+\frac{1}{2}}

S=\frac{\frac{1}{2}}{\frac{3}{2} }

S = \frac{1}{3}

Now we are sure that the sum of infinite terms is \frac{1}{3}.

Therefore, sum of 10 terms will not exceed \frac{1}{3}

Now sum of first two terms = \frac{1}{2}-\frac{1}{4}=\frac{1}{4}

Now we are sure that sum of first 10 terms lie between \frac{1}{4} and \frac{1}{3}

Since \frac{1}{2}>\frac{1}{3}

Therefore, Sum of first 10 terms will lie between \frac{1}{4} and \frac{1}{2}.

Option D will be the answer.

3 0
3 years ago
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