Answer:
$71.00
Step-by-step explanation:
100
-29 = 71.00
Answer:
48 sq. ft.
Step-by-step explanation:
P=12 times 12 which equals 144
A=12+12+12+12=48
Answer:
60 square units
Step-by-step explanation:
You can get there a couple of ways.
One way is to consider the enclosing rectangle, which is 9 units by 11 units, so has an area of 99 square units. From that will be subtracted two triangles having height 2 and width 6, and two triangles having height 3 and width 9. Thus the net area in rectangle DEFG is ...
99 - 2·6 - 3·9 = 60 . . . square units
__
Another way is to find the lengths of each of the sides and multiply those.
Short side = √(2²+6²) = 2√10
Long side = √(3²+9²) = 3√10
area = short side × long side = (2√10)(3√10) = 6·10 = 60 . . . square units
Answer:
NO
Step-by-step explanation:
To find out which observation to classify as an outlier, whether the largest or not, a very good approach or way to do this is to apply the 1.5(IQR) rule.
According to the rule, for finding the largest observation in the data that can be classified as an outlier, we would use the formula = Q3 + 1.5(IQR).
Q3 = 120
IQR = Q3 - Q1 = 120 - 95 = 25
Lets's plug these values into Q3 + 1.5(IQR)
We have,
120 + 1.5(25)
= 157.5
Since our max in the observation is given as 155, the largest observation in the data set cannot be set as an outlier because 157.5 which we got from our calculation is higher than the max value we have in the data set.
Our answer is NO.
However, the smallest observation should be set as outlier because:
Q1 - 1.5(IQR) = 95 - (1.5*25) = 57.5, which gives us an outlier that falls within our data range.
Answer:
22
Step-by-step explanation:
40 - 34 = 6
28 - 6 = 22
I'm not sure if there's any dividing or multiplying involved in this but I did my best..
