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Tanya [424]
3 years ago
8

Two cyclists, 96 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other. If they

meet 4 hours later, what is the speed (in mi/h) of the faster cyclist? What is the speed of the faster cyclist?
Mathematics
1 answer:
JulsSmile [24]3 years ago
7 0
<span>18 mph. OK. Let's call the speed of the slower cyclist X, And since the faster cyclist is 3 times faster, that speed will be 3X. So their combine closing speed will be (X + 3X) and over a period of 4 hours, they travel 96 miles. So the equation becomes: 4(X + 3X) = 96 Now solve for X 4(X + 3X) = 96 4(4X) = 96 16X = 96 X = 6 So the slower cyclist has a speed of 6 mph. And since the faster cyclist is 3 times faster, that speed is 3*6 = 18 mph.</span>
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