Answer:Dr. Hess' most significant contribution to the plate tectonic theory began in 1945 when he was the commander of the U.S.S. ... In the paper Hess described how hot magma would rise from under the crust at the Great Global Rift. When the magma cooled, it would expand and push the tectonic plates apart.
Explanation:
Option d) is the correct free body diagram.
Explanation:
A free-body diagram is a diagram that shows all the forces acting on a body. Each force is represented using an arrow, where:
- The length of the arrow is proportional to the magnitude of the force
- The direction of the arrow corresponds to the direction of the force
For the block in this problem, we have the following forces:
- The force F applied from the child, which acts at an angle with respect to the horizontal --> this rules out option a) and c), where the force acts horizontally
- The force of gravity (the weight of the object), labelled with W, which always acts downward --> this rules out option b), since the weight acts downward.
Therefore, the correct option is d).
(in reality, there should be another force: the normal reaction exerted by the floor on the block, N, acting upward).
Learn more about forces and weight:
brainly.com/question/8459017
brainly.com/question/11292757
brainly.com/question/12978926
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Answer:
21.6
Explanation:
0.6% * 36 = 21.6
are you looking for percentage or just answer??
Answer:
A) U₀ = ϵ₀AV²/2d
B) U₁ = (ϵ₀AV²)/6d
This means that the new energy of the capacitor is (1/3) of the initial energy before the increased separation.
C) U₂ = (kϵ₀AV²)/2d
Explanation:
A) The energy stored in a capacitor is given by (1/2) (CV²)
Energy in the capacitor initially
U₀ = CV²/2
V = voltage across the plates of the capacitor
C = capacitance of the capacitor
But the capacitance of a capacitor depends on the geometry of the capacitor is given by
C = ϵA/d
ϵ = Absolute permissivity of the dielectric material
ϵ = kϵ₀
where k = dielectric constant
ϵ₀ = permissivity of free space/air/vacuum
A = Cross sectional Area of the capacitor
d = separation between the capacitor
If air/vacuum/free space are the dielectric constants,
So, k = 1 and ϵ = ϵ₀
U₀ = CV²/2
Substituting for C
U₀ = ϵ₀AV²/2d
B) Now, for U₁, the new distance between plates, d₁ = 3d
U₁ = ϵ₀AV²/2d₁
U₁ = ϵ₀AV²/(2(3d))
U₁ = (ϵ₀AV²)/6d
This means that the new energy of the capacitor is (1/3) of the initial energy before the increased separation.
C) U₂ = CV²/2
Substituting for C
U₂ = ϵAV²/2d
The dielectric material has a dielectric constant of k
ϵ = kϵ₀
U₂ = (kϵ₀AV²)/2d
I'm thinking that the answer may be change of speed.