<span><u><em>This process is called condensation.</em></u></span>
<u><em>First,The sun heats up the seas and evaporates the water.Then,The water fly into the air as gas.When cold,water condense and for cloud that pours rain.</em></u>
<u /><em><u /><u>GoodLuck</u><u> Nobble user!!!!
</u></em>
Answer:
Explanation:
To focus object at .7m , the image distance can be measured as follows
object distance u = .7m
focal length f = .05 m
image distance v = ?
from lens formula
v = .054 m
= 54 mm
when the object is at infinity , image is formed at focus ie at distance of
50 mm .
So lens position from sensor where image is formed , varies from 54 mm to 50 mm .
Answer:
4 m/s
Explanation:
From the law of conservation of momentum,
Total momentum before collision = Total momentum after collision
mu+m'u' = V(m+m')...................... Equation 1
Where m = mass of the arrow, u = initial velocity of the arrow, m' = mass of the apple, u' = initial velocity of the apple, V = Final velocity of the apple and the arrow after collision.
make V the subject of the equation
V = (mu+m'u')/(m+m').................... Equation 2
Given: m = 0.5 kg, m' = 2 kg, u = 20 m/s, u' = 0 m/s(initially at rest)
Substitute into equation 2
V = (0.5×20+2×0)/(2+0.5)
V = 10/2.5
V = 4 m/s.
Hence the final velocity of the apple and the arrow after the collision = 4 m/s
Answer:
V=1.19m/s
Explanation:
A 30-06 caliber hunting rifle fires a bullet of mass 0.018 kg with a velocity of 417 m/s to the right. The rifle has a mass of 6.29 kg. What is the recoil speed of the rifle as the bullet leaves the rifle?
this momentum.
it has to deal with the interaction between bullet and a gun
.lets have a deep dive into the solution
momentum is the product of mass of a body and the velocity
momentum of the bullet-=momentum of the gun
mv=MV
mass of bullet=0.018kg
v=velocity of bullet
M=mass of rifle 6.29kg
V=recoil velocity of the rifle gun
0.018*417=6.29*V
V=1.19m/s
mass is the quantity of matter in a body
velocity is change in displacement per time
When a positive rod is placed to the right of sphere B, and the spheres are separated, the reason behind this is the same charge on the sphere as the rod i.e. the right of the sphere also had a positive charge. Thus, the same positive charges could not reside on the right side surface of the sphere due to which it separation happens.
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