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3 years ago

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A block with mass m = 4.5 kg is attached to two springs with spring constants kleft = 36 N/m and kright = 50 N/m. The block is p

ulled a distance x = 0.25 m to the left of its equilibrium position and released from rest. 1)What is the magnitude of the net force on the block (the moment it is released)?

1 answer:

DaniilM [7]3 years ago

6 0

Answer:

21.5 N

Explanation:

As the block is pulled to a distance of 0.25 m to the left of its equilibrium position, the left spring is compressed by x = 0.25 m and exerting an elastic force to the right, the right spring is stretched by x =0.25 m and also exerting an elastic force to the right. Knowing their spring constant, we can calculate the total net force at that instant

$F = F_{left} + F_{right}$

$F = k_{left}x + k_{right}x$

$F = x(k_{left} + k_{right}) = 0.25(36 + 50) = 0.25*86 = 21.5 N$

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