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zaharov [31]
3 years ago
10

Helppppp, if you could show your work too that would be so amazing!!

Mathematics
1 answer:
astra-53 [7]3 years ago
8 0

9514 1404 393

Answer:

  x = 6

  PM = 50

  MQ = 50

  PQ = 100

Step-by-step explanation:

The two halves of the segment are the same length:

  PM = MQ

  7x +8 = 5x +20

  2x = 12 . . . . . . . . . subtract 5x+8

  x = 6 . . . . . . . . . . . divide by 2

  PM = 7(6)+8 = 42+8

  PM = 50

  MQ = 5(6) +20 = 30+20

  MQ = 50

  PQ = PM +MQ = 50 +50

  PQ = 100

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What is the length of the line segment joining the points A(3, - 5) and B(-5,1)?​
Anna [14]
√26 would be your answer
8 0
3 years ago
In APQR, P = 83°, p = 285 m, r = 216 m.<br>Calculate R.​
vladimir1956 [14]

Answer:

48.8°

Step-by-step explanation:

We solve using sine rule

The formula is given as

p/sin P = r/sin R

In APQR, P = 83°, p = 285 m, r = 216 m.

Calculate R.

Hence, solving for R

285/sin 83 = 216/sin R

Cross Multiply

285 × sin R = sin 83 × 216

sin R = sin 83 × 216/285

R = arc sin (sin 83 × 216/285)

R = 48.78527°

Approximately = 48.8°

Therefore, R = 48.8°

5 0
3 years ago
We are given that a force of 60 N is exerted at an angle of 37°. Therefore, the force vector F can be represented as the hypoten
maw [93]

We are told that the force of 60 N is exerted at an angle of 37°. Since this one is on the terminal side therefore this force must be the resultant vector. We know that the resultant vector is equal to the hypotenuse of the triangle. So we can say that:

|F| = 60 N

 

So we see that the given angle is simply something to trick us since we are simply asked for the hypotenuse. If we are to compute for the vertical and horizontal components, that is the time we need to use the angle.

 

Answer:

|F| = 60 N

6 0
3 years ago
6973x63 pls explain how u did it!
Goryan [66]

Answer:

4,39299

Step-by-step explanation:

I multiplied 3 x all the numbers in 6,973, then 6 x all the numbers (I added a 0 before I multiplied, then added both the products and got my answer.

4 0
2 years ago
5. Find the equation of a circle whose center is at (5, -8) and radius 8.
Brums [2.3K]

Answer:

x^{2} + y^{2} -10x -16y + 39

<u>Step-by-step explanation:-</u>

The equation used to find the equation of circle is :-

(x-a)^{2} + (y-b)^{2} = radius^{2}

'a' means the x coordinate of the circle, 'b' means y coordinate of the circle.

In the question, it's given that the coordinates of the circle are (5, -8) and radius is 8cm.

So, 'a' will be 5 and 'b' will be -8

So,

(x-5)^{2} + (y--8)^{2} = 8^{2}

(x-5)^{2} + (y+8)^{2} = 64

x^{2} - 10x + 25 + y^{2} - 16y + 64

x^{2} + y^{2} -10x -16y + 64 - 25

= x^{2} + y^{2} -10x -16y + 39

4 0
3 years ago
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