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3 years ago

What is 120 divided by 8?!?

Mathematics

2 answers:

ICE Princess25 [194]3 years ago

5 0

The answer to this question is 15.

Yuliya22 [10]3 years ago

5 0

120/8
Divide
Final Answer: 15

You can make sure the answer is 15 by multiplying 15 by 8 in which should get 120. That's how you know 15 is the correct answer.

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2/5(d−10)−23(d+6)25(d−10)−23(d+6) is

Dimas [21]

Simplify $\frac{2}{5}$ (d - 10) to $\frac{2(d - 10)}{5}$ :
\frac{2(d - 10)}{5} [/tex] - 23(d + 6) x 25(d - 10) - 23(d + 6)

Simplify 23(d + 6) x 25(d - 10) to 575(d + 6)(d - 10) :
\frac{2(d - 10)}{5} [/tex] - 575(d + 6)(d - 10) - 23(d + 6)

Then Expand :
\frac{2(d - 10)}{5} [/tex] - 575 $d^{2}$ + 5750d - 3450d + 34500 - 23d - 138

Now Collect Like Terms :
\frac{2(d - 10)}{5} [/tex] - 575 $d^{2}$ + (5750d - 3450d + 34500 - 23d) + (34500 - 138)

Answer :
\frac{2(d - 10)}{5} [/tex] - 575 $d^{2}$ + 2277d + 34362

7 0

3 years ago

X=88 ?89 ? Or 90?<br> What is x= ?

Valentin [98]

I believe that it may be 90 I could be wrong though

5 0

4 years ago

Read 2 more answers

Got the answer to this so i guess FRE POINTS A scientist made measurements of the average change in temperature each month for a

tester [92]

Answer:

Yay free point thx

4 0

3 years ago

Read 2 more answers

Answer please with the work thank you. Who ever answers geta the brainlest answer!

vodomira [7]

Answer:

Step-by-step explanation:

cassie is going up 3 and then down 5

8 + 3=11

11-5= 6

8 0

3 years ago

Of the 45 animals on the farm, there are only pigs and chickens. The animals have a total of 124 legs. How many pigs and how man

Bess [88]

Answer:

$on \: this \: farm \: there \: are \to \\ \underline{ \boxed{17 \: pigs }}\: \\ and \\ \underline{ \boxed{28 \:chickens}}$

Step-by-step explanation:

$\\ \underline{ \boxed{solution \: to \: question \: \boxed{ A}}} \\ \\ let \: the \: pigs \: be \to \: p \\ let \: the \: chicks \: be \to \: c \\let \: the \: total \: animals \: be \to \: 45 \\ hence \to \\ p + c = 45.......eq(1) \\ since \: chickens \: have \: two \: legs : \\ while \: pigs \: have \: four \: legs : \\ let \: animals \: with \: 2 \: legs \: be \to \: 2c \\ let \: animals \: with \: 4\: legs \: be \to \: 4p \\ the \: total \: number \: of \: animal \: legs = 124 \\ hence \to \\ 4p + 2c = 124..........eq(2) \\ therefore \: the \: system \: of \: equations \: \\ to \: describe \: the \: situation \: is \to \\ \\ p + c = 45 \\ 4p + 2c = 124 \\ \\ \\ \underline{ \boxed{solution \: to \: question \: \boxed{B }}} \\ \\ \\ we \: could \: apply \: any \: of \: the \: simultanious \\ principles \to \\ here : am \: appling \: the \: elimination \: method \to \\ p + c = 45 \\ 4p + 2c = 124 \\ to \: elimnate \: one \: varaible \: we \: multiply \: by \to \\ (4) \times p + c = 45 \\ (1) \times 4p + 2c = 124 \\ hence \to \\ - \frac{4p + 4c = 180}{4p + 2c = 124} \\next \to \\ 2c = 56 \\ c = \frac{56}{2} \\ \boxed{ c = 28} \\ lets \: work \: for \: p \to \\ p + c = 45 \\ p + 28 = 45 \\ p = 45 - 28 \\ \boxed{p = 17}$

6 0

3 years ago