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bulgar [2K]
3 years ago
14

A miniature American Eskimo dog has a mean weight of 15 pounds with a standard deviation of 2 pounds. Assuming the weights of mi

niature Eskimo dogs are normally distributed, what range of weights would 68% of the dogs have?
A.)Approximately 13–17 pounds
B.)Approximately 14–16 pounds
C.)Approximately 11–19 pounds
D.)Approximately 9–21 pounds
Mathematics
2 answers:
Irina18 [472]3 years ago
8 0

Answer:

Approximately 13–17 pounds ⇒ answer A

Step-by-step explanation:

* Lets explain how to solve the problem

- The Empirical Rule states that almost all data lies within 3

standard deviations of the mean for a normal distribution.  

- 68% of the data falls within one standard deviation.  

- 95% of the data lies within two standard deviations.  

- 99.7% of the data lies Within three standard deviations  

- The empirical rule shows that

# 68% falls within the first standard deviation (µ ± σ)

# 95% within the first two standard deviations (µ ± 2σ)

# 99.7% within the first three standard deviations (µ ± 3σ).

* Lets solve the problem

- A miniature American Eskimo dog has a mean weight of 15 pounds

 with a standard deviation of 2 pounds

∴ µ = 15 and σ = 2

- The weights of miniature Eskimo dogs are normally distributed

- We need to know the range of weights would 68% of the

  dogs have

∵ 68% falls within the first standard deviation (µ ± σ)

∵ 15 - 2 = 13

∵ 15 + 2 = 17

∴ The range is approximately 13–17 pounds

kari74 [83]3 years ago
4 0

Answer:

the answer is A.

Step-by-step explanation:

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Suppose there is a 13.9 % probability that a randomly selected person aged 40 years or older is a jogger. In​ addition, there is
Blababa [14]

Answer:

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

It would be unusual to randomly select a person aged 40 years or older who is male and jogs.

Step-by-step explanation:

We have these following probabilities.

A 13.9% probability that a randomly selected person aged 40 years or older is a jogger, so P(A) = 0.13.

In​ addition, there is a 15.6% probability that a randomly selected person aged 40 years or older is male comma given that he or she jogs. I am going to say that P(B) is the probability that is a male. P(B/A) is the probability that the person is a male, given that he/she jogs. So P(B/A) = 0.156

The Bayes theorem states that:

P(B/A) = \frac{P(A \cap B)}{P(A)}

In which P(A \cap B) is the probability that the person does both thigs, so, in this problem, the probability that a randomly selected person aged 40 years or older is male and jogs.

So

P(A \cap B) = P(A).P(B/A) = 0.156*0.139 = 0.217

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

A probability is unusual when it is smaller than 5%.

So it would be unusual to randomly select a person aged 40 years or older who is male and jogs.

4 0
3 years ago
(x+3y=6<br> 16x + 18y = 36
jonny [76]

Answer:

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Step-by-step explanation:

Check attachment

7 0
3 years ago
6 - y = 12 is what lol
notsponge [240]

Answer:

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Step-by-step explanation:

7 0
2 years ago
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John can jog twice as fast as he can walk. He was able to jog the first mile to his grandmas house but then he got tired and wal
statuscvo [17]

Answer:

  12 mph

Step-by-step explanation:

The relationship between jogging speed and walking speed means the time it takes to walk 4 miles is the same as the time it takes to jog 8 miles. Then the total travel time (0.75 h) is the time it would take to jog 1+8 = 9 miles. The jogging speed is ...

  (9 mi)(.75 h) = 12 mi/h . . . average jogging speed

__

<em>Check</em>

1 mile will take (1 mi)/(12 mi/h) = 1/12 h to jog.

4 miles will take (4 mi)/(6 mi/h) = 4/6 = 8/12 h to walk.

The total travel time is (1/12 +8/12) h = 9/12 h = 3/4 h. (answer checks OK)

_____

<em>Comment on the problem</em>

Olympic race-walking speed is on the order of 7.7 mi/h, so John's walking speed of 6 mi/h should be considered quite a bit faster than normal. The fastest marathon ever run is on the order of a bit more than 12 mi/h, so John's jogging speed is also quite a bit faster than normal. No wonder he got tired.

7 0
3 years ago
Find the ratio a:b, if it is given that a+b=3b
Darya [45]

Answer:

Step-by-step explanation:

a + b = 3b

a = 3b - b

a = 2b

a/b = 2/1

a:b = 2:1

8 0
3 years ago
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