Answer:
How to Save the Rainforest
Teach others about the importance of theenvironment and how they can help save rainforests.
Restore damaged ecosystems by planting trees on land where forests have been cut down.
Encourage people to live in a way that doesn't hurt the environment.
Establish parks to protect rainforests and wildlife.
B is the answer to your question.
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Answer:
The fraction of heterozygous individuals in the population is 32/100 that equals 0.32 which is the genotipic proportion for these endividuals.
Explanation:
According to Hardy-Weinberg, the allelic frequencies in a locus are represented as p and q, referring to the alleles. The genotypic frequencies after one generation are p² (Homozygous for allele p), 2pq (Heterozygous), q² (Homozygous for the allele q). Populations in H-W equilibrium will get the same allelic frequencies generation after generation. The sum of these allelic frequencies equals 1, this is p + q = 1.
In the exposed example, the r-6 allelic frequency is 0,2. This means that if r-6=0.2, then the other allele frequency (R) is=0.8, and the sum of both the allelic frequencies equals one. This is:
p + q = 1
r-6 + R = 1
0.2 + 0.8 = 1
Then, the genotypic proportion for the homozygous individuals RR is 0.8 ² = 0.64
The genotypic proportion for the homozygous individuals r-6r-6 is 0.2² = 0.04
And the genotypic proportion for heterozygous individuals Rr-6 is 2xRxr-6 = 2 x 0.8 x 0.2 = 0.32
The nuclide represented as X is thorium and this is an alpha decay where an alpha particle is removed off.
<h3>What is nuclide?</h3>
A kind of atom or nucleus which is represented by a specific number of protons and neutrons.
The equation given represents an alpha decay. In an alpha decay, an alpha particle is removed off.
The atomic number of the parent nuclide is more than the daughter nuclide by two units and the mass number of the parent is more than that of the daughter nuclide by four units.
Thus, the x is thorium.
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1. The wavelength is the ratio of the wave's speed to its frequency in hertz or 1/s. This is shown below,
λ = s / f = (320 m/s) / (300 1/s) = 1.07 m
The wavelength is approximately 1.07 m.
2. The frequency is the ratio between speed and the wavelength,
f = (330 m/s) / 0.45 m = 733.33 hertz
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