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Tpy6a [65]
3 years ago
15

What is the volume of aa circle with the radius of 1?

Mathematics
1 answer:
patriot [66]3 years ago
7 0

Answer:

3.14159 (pi)

Step-by-step explanation:

1^1=1*3.14=3.14

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How do you factor this problem?
9966 [12]
3m^3 -2m^2 + 4m + 2 

To factor the first problem you have to divide all by 4

The second one is m - <span>√16m +8

To factor the second problem you have to square root it all</span>
8 0
4 years ago
A picture frame can hold a Photograph that is 16 inches long and 12 inches wide. What is the area of the photo that fits the fra
TEA [102]

Answer:

16x12=192

Step-by-step explanation:

Two times sixteen equals thirty two, ten times sixteen equals one hundred sixty, thirty two plus one hundred sixty equals one hundred ninety two

8 0
3 years ago
18 2/5 - n = -10 1/3
Wewaii [24]

Answer:

The answer is n=28\frac{11}{15}.

Step-by-step explanation:

Given:

18 2/5 - n = -10 1/3.

Now, to solve the equation:

18\frac{2}{5} - n = -10 \frac{1}{3}

Converting the mixed fractions to improper:

⇒\frac{92}{5} -n=-\frac{31}{3}

Moving the numbers on one side and variable to the other:

⇒\frac{92}{5} +\frac{31}{3}=n

Now, solving the factions:

⇒\frac{92\times 3+31\times 5}{15}=n

⇒\frac{276+155}{15}=n

⇒\frac{431}{15}=n

⇒28\frac{11}{15}=n

Therefore, the answer is n=28\frac{11}{15}.

3 0
3 years ago
NEED HELP ASAP PLEASE
professor190 [17]
No idea sorry! If I knew I would tell you
7 0
2 years ago
Read 2 more answers
Eva payrolls for on a number cube and the number of cubes roll 24 times then what is a reasonable prediction for the number of s
Allushta [10]

Answer:

The reasonable prediction for successful rolls is 4.

Step-by-step explanation:

Assuming the rolling cube  is a fair 6 sided cube, so the probability of success of one roll is given as

P(Success)=\dfrac{Number\ of\ successful\ events}{Number\ of\ total\ events}

P(Success)=\dfrac{1}{6}

The total success is given as

P(Total\ Success)=P(Success)\times Number\ of\ events

For 24 rolls it is given as

P(Total\ Success)=P(Success)\times Number\ of\ events\\P(Total\ Success)=\dfrac{1}{6}\times 24\\P(Total\ Success)=4

So the reasonable prediction for successful rolls is 4.

3 0
3 years ago
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