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Scorpion4ik [409]
3 years ago
10

How to solve 4x - 2y = 22 and 2x + 4y = 6 using elimination

Mathematics
2 answers:
Scrat [10]3 years ago
7 0

X=5
Y=1
2x+4(2x-11)=6
+44 both sides
2x+8x=50
10x=50
Divide by 10 both sides
X=5
Plug in 5 to x and you will find y

nevsk [136]3 years ago
4 0

The given equations are

4x - 2y = 22 --- Equation Number 1

2x + 4y = 6 --- Equation Number 2

Let's multiply the first equation by 2 . The equation becomes :

8x - 4y = 44

Now let's add both the equations:

(2x + 4y) + (8x - 4y) = 6 +44

or, 2x + 8x + 4y - 4y = 50

or, 10x = 50

or, x = 50/10

or,x = 5

Now put, x =5 in equation number 2, 2x + 4y = 6

2 * 5 + 4 y = 6

or, 10 + 4y = 6

or, 4y = 6-10

or, 4y = -4

or, y = -4/4

or, y =-1

Therefore, x = 5 and y = -1

Hope this helps..!!

Thank you :)


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Yuki888 [10]

Answer:

Step-by-step explanation:

For the graphing, we can graph both equations, and where they intercept is the answer. Okay, so we can give x random inputs and get y as an output which is one pair of coordinates. I usually like using 0 as x.  y-3(0)=12.  y-0=12. y=12. So for our first equation, on of the coordinates is (0,12). Now we can insert another input for x! ( I chose 1.)  y-3(1)=12.  y-3=12.  y=15.   So our other pair of coordinates for the first equation is (1,15). We can do the same with the second equation. 2y+8(0)= -4. 2y+0= -4.  y=-2.  The first pair of coordinates for the second equation is (0,-2).  Another input we can put in is 1, again. 2y+8(1)=-4. 2y+8=-4.   2y= -12.  y= -6. So our second pair of coordinates for our second equation is (1,-6). We can graph this with a graphing calculator, or mark these points and draw a straight line through them. When we draw a line through them, the part where the two lines intersect is the answer.

When we do substitution, we need to solve for x or y in the bottom equation. I want to solve for x. ( NOTE: IF YOU SOLVE FOR y, YOU STILL GET THE SAME ANSWER) x=-56-3y. Then we replace the x on the top equation with 56-3y. And we get: 2(56-3y)-y=0. We can use the distributive property. The answer I have is 112-6y-y=0.  -6y-y is -7y.  112-7y=0.    We can add 7y to both sides so they seperate the variables and the numbers. 112=7y.  Lastly, divide by 7. For y, we get 16. To get x, we insert y, AKA 16 into x+3y= -56. x+3(16)=-56.  x+48= -56. Our last step to get x is to subtract 48 from both sides leaving us with: x= -100. Our final answer is y= 16 and x= -100.

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3 years ago
HELP ME PLEASE ASAP?!?What is the value of y?
Snezhnost [94]
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AD←→ is tangent to circle M at point D. The measure of ∠DMQ is 58º.
Marat540 [252]

Answer:

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Step-by-step explanation:

Given:

∠DMQ = 58º

In this circle, the radius is DM. Since AD is tangent to the circle M, at point D, and the angle between a tangent and a radius is 90°

Therefore, ∠MDQ = 90°

The total angle in a triangle is 180°. Since we have the values of ∠MDQ and ∠DMQ, ∠DQM will be calculated as:

180 = ∠DMQ + ∠MDQ + ∠DQM

Solving for ∠DQM, we have:

∠DQM = 180 - ∠DMQ - ∠MDQ

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