Answer:
i think 300$
Step-by-step explanation:
Answer:
y = 0.6x – 4
or
y =
3/5x
-4
Step-by-step explanation:
Answer:
7w+11
Step-by-step explanation:
GEMDAS
To solve this equation with algebra
4/7 = 1/x
(4/7)x = (1/x)x
4x/7 = 1
(4x/7)7 = 1(7)
4x = 7
4x/4 = 7/4
x = 1.75
1.75 yards of fabric are needed to make 1 dress.
Hope this helps! <3
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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