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irina [24]
3 years ago
8

I need assistance with this.​

Mathematics
2 answers:
Art [367]3 years ago
6 0

I did the problems not on paper so the answers are in the screenshot. Also you do these problems by putting the number in which every column matches to the letter on the equation. For example on the table in the first question x=0, so you'd put in 7(0)-y=7 to get y.

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! ;3

- Cutiepatutie ☺❀❤

Alexus [3.1K]3 years ago
3 0

Answer:

write an answer

Step-by-step explanation:

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<span>Two consecutive even integers have a sum of 46 are</span> 22 and 24

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Step-by-step explanation:

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The area of the right triangle shown is 24 square feet. Which equations can be used to find the lengths of the legs of the trian
Gwar [14]

The equations to calculate the legs are 0.5(x)(x + 2) = 24, x^2 + 2x - 48 = 0 and x^2 + (x + 2)^2 = 100

<h3>How to determine the legs of the triangle?</h3>

The complete question is in the attached image

The given parameters are:

Area = 24

Legs = x and x + 2

The area of the triangle is calculated as:

Area = 0.5 * Base * Height

This gives

0.5 * x * (x + 2) = 24

So, we have:

0.5(x)(x + 2) = 24

Divide through by 0.5

(x)(x + 2) = 48

Expand

x^2 + 2x = 48

Subtract 48 from both side

x^2 + 2x - 48 = 0

Hence, the equations to calculate the legs are 0.5(x)(x + 2) = 24, x^2 + 2x - 48 = 0 and x^2 + (x + 2)^2 = 100

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2 years ago
Please help i’m actually crying rn give step by step
andrezito [222]

Answer:

X = 70 degrees

Step-by-step explanation:

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pav-90 [236]

Answer:

9

Step-by-step explanation:

Let us say, Olivia's age is x.

Now as the question says, we will get this equation.

( \frac{1}{3}  x ) + 12= 2x - 3

Multiply both sides by 3.

x + 36 = 6x - 9

Collect like terms.

x - 6x =  - 9 - 36

Calculate.

- 5x =  - 45

Divide both sides of the equation by -5.

x = 9

Then, we will get the answer.

<u>I</u><u> </u><u>h</u><u>o</u><u>p</u><u>e</u><u> </u><u>i</u><u>t</u><u> </u><u>h</u><u>e</u><u>l</u><u>p</u><u>s</u><u>.</u>

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