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Salsk061 [2.6K]
3 years ago
12

On a standardized exam, the scores are normally distributed with a mean of 250 and

Mathematics
1 answer:
fredd [130]3 years ago
7 0

Answer:

the z-score is within 3

Step-by-step explanation:

first you got to take the standard deviation and add it to the mean since 375 is greater than 250. so the equastion would be

250+50=300+50=350+50=40

so the z-score for the value of 375 is within 3      

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Find the value of b. Express the answer as a simplified radical.
Mama L [17]

Here three sides of a right angled triangle given.

The three sides are b, 8 and 14.

The side with length 14 is the hypotenuse here. We have to find the side of length b.

To get b, we will use Pythagoras theorem here.

By using Pythagoras theorem we can write,

c^2=a^2+b^2, where c is the hypotenuse.

So here we can write,

14^2=8^2+b^2

196 = 8^2+b^2

196=64+b^2

To solve it for b, now we have to move 64 to the left side by subtracting it from both sides.

196-64 = 64+b^2-64

196-64 = b^2

132=b^2

Now to find b, we have to take square root to both sides. We will get,

\sqrt{132}= \sqrt{b^2}

\sqrt{132} =b

b= \sqrt{(4)(33)}

b= (\sqrt{4})(\sqrt{33})

b= 2\sqrt{33}

We have got the required answer for the side b.

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Answer:

18

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What is 8/56 simplified
Sergio [31]

Answer:

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A vertical line has points C, E, F from top to bottom. 2 lines extend from point E. One line extends to point A and another exte
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Suppose that 10% of the fields in a given agricultural area with about 2,500 fields are infested with the sweet potato white fly
aleksley [76]

Answer:

a. 250 fields

b. 220 to 280 fields

c. Fields are not independent

Step-by-step explanation:

a. The average number of fields sampled that are infested with whitefly =

number of fields X Percentage sampled, 10%

= 2500 X 10% = 250 fields

b.  Going by the binomial distribution is the square of the standard deviation, divided by (the product of the sample size n, and the probability a and b). While the standard deviation is the square root of the variance

σ = √nab

= √na(1-a) = √2500 X 10% X (1- 10%)

= √225 = 15

Now let's use the empirical rule that says about 95% of the observations are within two standard deviations from the mean since the number of trials is very large

μ - 2σ = 250 - 2(15) = 220

μ + 2σ = 250 + 2(15) = 280

Approximately 220 to 280 fields are expected to be infested going by 95% probability observation

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