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3 years ago

Deductive reasoning goes from the general to the blank

Mathematics

1 answer:

Olenka [21]3 years ago

5 0

If this is a true or false statement then TRUE

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Solve the following system of equations by graphing. y = -1/2x-1 y = 1/4x -4

nordsb [41]

Answer:

x=4,y=−3

Step-by-step explanation:

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3 years ago

NATURAL NUMBER DEFINITION

prisoha [69]

Answer: the number 1 or any number (such as 3, 12, 432) obtained by adding 1 to it one or more times: a positive integer. 2: any of the positive integers together with 0: a nonnegative integer.

Step-by-step explanation:

the number 1 or any number (such as 3, 12, 432) is obtained by adding 1 to it one or more times: a positive integer. 2: any of the positive integers together with 0: a nonnegative integer

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1 year ago

Which congruence theorem can be used to prove △WXS ≅ △YZS? Triangles W X S and Y Z S are connected at point S. Angles W X S and

iVinArrow [24]

Point S makes the two connected angles the same. They both have right angles.

And one side of each is congruent.

This means you know 2 angles are the same and one side is the same.

You would use ASA (Angle, Side, Angle)

3 0

3 years ago

Read 2 more answers

You are working part-time for an electronics company while going to high school. The following table shows the hourly

inn [45]

Answer: 5

Step-by-step explanation:

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3 years ago

An air transport association surveys business travelers to develop quality ratings for transatlantic gateway airports. The maxim

Flura [38]

Answer:

The 95% confidence interval estimate of the population mean rating for Miami is (6.0, 7.5).

Step-by-step explanation:

The (1 - α)% confidence interval for the population mean, when the population standard deviation is not provided is:

$CI=\bar x \pm t_{\alpha/2, (n-1)}\cdot \frac{s}{\sqrt{n}}$

The sample selected is of size, n = 50.

The critical value of t for 95% confidence level and (n - 1) = 49 degrees of freedom is:

$t_{\alpha/2, (n-1)}=t_{0.05/2, 49}\approx t_{0.025, 60}=2.000$

*Use a t-table.

Compute the sample mean and sample standard deviation as follows:

$\bar x=\frac{1}{n}\sum X=\frac{1}{50}\times [1+5+6+...+10]=6.76\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{49}\times 31.12}=2.552$

Compute the 95% confidence interval estimate of the population mean rating for Miami as follows:

$CI=\bar x \pm t_{\alpha/2, (n-1)}\cdot \frac{s}{\sqrt{n}}$

$=6.76\pm 2.000\times \frac{2.552}{\sqrt{50}}\\\\=6.76\pm 0.722\\\\=(6.038, 7.482)\\\\\approx (6.0, 7.5)$

Thus, the 95% confidence interval estimate of the population mean rating for Miami is (6.0, 7.5).

7 0

3 years ago