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8_murik_8 [283]
3 years ago
10

3x - 6x + 2 > 65 Mathematic

Mathematics
2 answers:
LenKa [72]3 years ago
5 0

3x - 6x + 2 > 65

Combine like terms.

-3x + 2 > 65

Subtract 2 from both sides.

-3x > 62

Divide both sides by -3

x < -62/3

atroni [7]3 years ago
4 0

Answer:

3x - 6x + 2 > 62

→ -3x + 2 > 62

→ -3x > 62

→ x < -62/3

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Does this graph represent a proportional relationship?<br> Explain.
ArbitrLikvidat [17]

Answer:

no it doesnt a Proportional relationships are relationships between two variables where their ratios are equivalent. Another way to think about them is that, in a proportional relationship, one variable is always a constant value times the other. . so this is not one because its needs to be straight that is a Non linear function.

Step-by-step explanation:

6 0
3 years ago
Solve the system 3x+y=7 and -2x-y=9<br><br> X=7<br> x=16<br> x=9<br> X=1
igomit [66]

Answer:

Step-by-step explanation:

3x + y = 7

-2x - y = 9

x = 16

answer is B

3(16) + y = 7

48 + y = 7

y = -41

3 0
4 years ago
PLSS HELP IMMEDIATELY!!!! ILL MARK BRAINIEST IF U DONT LEAVE A LINK OR GUESS!!!!
Georgia [21]

Answer:19

Step-by-step explanation:

7x3=21

21-2=19

5 0
3 years ago
Read 2 more answers
Integrals using U sub. Please show steps so I can learn too :)
Romashka [77]

Answer:

\frac{arctan^2(x)}{2}

Step-by-step explanation:

For this question, set u = arctan(x).  This would be the easiest way because the derivative of arctan(x) is \frac{1}{x^2+1} which is what we have.  Before setting u, always look at the question and think about possible derivatives.

\int\frac{arctanx}{x^2+1}dx \ Let \ u = arctan(x)\\\\\\u = arctan(x) \ \ \ du = \frac{1}{x^2+1}dx\\

Next, plug in u and du.

\int (arctan(x)*\frac{1}{x^2+1})dx (rearranging)

\int u\ du

= \frac{u^2}{2} = \frac{1}{2}u^2

Substitute arctan(x) back in for u and add +C.

\frac{arctan^2(x)}{2}+C

7 0
3 years ago
Question 2 -
atroni [7]

Coefficient of variation, CV. for Data set A is 13.5% and for Data set B is 19.6%

Sample A: 2.94, 3.06, 3.07, 3.16, 3.34, 3.43, 3.47, 3.56, 3.57, 3.97, 3.99, 4.24, 4.30, 4.35

Mean = 3.6036, Standard deviation = 0.4858.

C.V = \frac{S.D}{Mean}

=\frac{0.4858}{3.6036}

=0.1348

=0.1

Sample B: $24,800, $30,000, $22,300, $20,400, $19,000, $32,200, $23,000, $23,000, $24,000, $27,200, $34,900

Mean = 25527.2727, Standard deviation = 5001.218.

C.V = \frac{S.D}{Mean}

=\frac{5001.218}{25527.2727}

=0.1959

=0.2

In terms of percentage, C.V for sample A is 13.5% and for sample B is 19.6%

Learn more here:

brainly.com/question/12974947?referrer=searchResults

3 0
3 years ago
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