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2 years ago

I need help please 4x-6y=36 how to show my work please help it would mean a lot :)

Mathematics

1 answer:

andre [41]2 years ago

3 0

Answer:

Solving for x:

$x = \frac{3}{2} y + 9$

Solving for y:

$y = \frac{2}{3} x - 6$

Step-by-step explanation:

Please see the attached picture for full solution.

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The steps below show the incomplete solution to find the value of x for the

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Just add 4 on both sides then divide both sides by 4 and then you’ll get your answer. I hope that helps!

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3 years ago

The function g(x) = 2x2 – 28x + 3 written in vertex form is g(x) = 2(x – 7)2 – 95. Which is one of the transformations applied t

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2 years ago

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Algebra 1 A Adaptive CR (JL22) 1/Tools Of The Trade

Archy [21]

The simplified expression of $(4^3)(\frac{4^4^0x^4}{3^2x^2y^2})$ is $\frac{4^7x^2}{3^2y^2}$

<h3>How to simplify the expression?</h3>

The expression is given as:

$(4^3)(\frac{4^4^0x^4}{3^2x^2y^2})$

Expressions raise to power 0 is 1.

So, we have:

$(4^3)(\frac{4^4x^4}{3^2x^2y^2})$

Apply the law of indices to expression with common base

$(\frac{4^{4+3}x^{4-2}}{3^2y^2})$

Evaluate the sum and difference

$(\frac{4^7x^2}{3^2y^2})$

Remove the bracket

$\frac{4^7x^2}{3^2y^2}$

Hence, the simplified expression of $(4^3)(\frac{4^4^0x^4}{3^2x^2y^2})$ is $\frac{4^7x^2}{3^2y^2}$

Read more about exponents at:

brainly.com/question/847241

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8 0

1 year ago

Fill in the table so it represents a linear function.

olga2289 [7]

Answer:

(From left to right) 2 5 8

Step-by-step explanation:

1. Find the gap (between the first and last terms) 11 - (-1) = 12

2. Divide by the number of times the linear term is added: 12/4=3

3. Use the common difference to find the missing values.

6 0

3 years ago

The wheels on Darlene's car have on 11-inch radius. If the wheels are rotating at a rate of 378 rpm, find the linear speed in mi

elena-s [515]

Answer:

The linear speed in which Darlene is traveling is 24.74 miles per hour.

Step-by-step explanation:

The wheel experiments rolling, which is a combination of translation and rotation. The point where linear speed happens is located at geometrical center of the wheel and instantaneous center of rotation is located at the point of contact between wheel and ground. The linear speed ( $v$ ), measured in inches per second, is defined by following expression:

$v = R\cdot \omega$ (1)

Where:

$R$ - Radius of the wheel, measured in inches.

$\omega$ - Angular speed, measured in radians per second.

If we know that $R = 11\,in$ and $\omega \approx 39.584\,\frac{rad}{s}$ , then the linear speed, measured in miles per hour, in which Darlene is traveling is:

$v = 11\,in\times \frac{1\,mi}{63360\,in} \times 39.584\,\frac{rad}{s}\times \frac{3600\,s}{h}$

$v \approx 24.74\,\frac{mi}{h}$

The linear speed in which Darlene is traveling is 24.74 miles per hour.

8 0

2 years ago