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pochemuha
3 years ago
12

What is the original price

Mathematics
1 answer:
eimsori [14]3 years ago
8 0
Sorry sir... but the screen is blurry. ; u ;
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Which expression can be used to find 80% of 120?
Vinil7 [7]

Answer:

C.(0.8) (120)

Step-by-step explanation:

0.8 = 80%

of means multiply, therefore, 0.8 x 120 equals 80% of 120.

6 0
3 years ago
Read 2 more answers
Any help with an explanation would be appreciated!
Lilit [14]

Problem 1

We'll use the product rule to say

h(x) = f(x)*g(x)

h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)

Then plug in x = 2 and use the table to fill in the rest

h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)

h ' (2) = f ' (2)*g(2) + f(2)*g ' (2)

h ' (2) = 2*3 + 2*4

h ' (2) = 6 + 8

h ' (2) = 14

<h3>Answer: 14</h3>

============================================================

Problem 2

Now we'll use the quotient rule

h(x) = \frac{f(x)}{g(x)}\\\\h'(x) = \frac{f'(x)*g(x)-f(x)*g'(x)}{(g(x))^2}\\\\h'(2) = \frac{f'(2)*g(2)-f(2)*g'(2)}{(g(2))^2}\\\\h'(2) = \frac{2*3-2*4}{(3)^2}\\\\h'(2) = \frac{6-8}{9}\\\\h'(2) = -\frac{2}{9}\\\\

<h3>Answer:  -2/9</h3>

============================================================

Problem 3

Use the chain rule

h(x) = f(g(x))\\\\h'(x) = f'(g(x))*g'(x)\\\\h'(2) = f'(g(2))*g'(2)\\\\h'(2) = f'(3)*g'(2)\\\\h'(2) = 3*4\\\\h'(2) = 12\\\\

<h3>Answer:  12</h3>
5 0
3 years ago
Help please! thank u
Alexus [3.1K]
A is NOT a function because for some values of x you get more than one y value. For example if x=2 you get 2 values for y.
b is a function because for each x you get ONLY one y
5 0
3 years ago
The one wirh my mouse over js 55
musickatia [10]

Answer:

55 is the answer

Step-by-step explanation:

180-76-49= 55 !!!!!

3 0
3 years ago
Read 2 more answers
If five times four is thirty-three, what will the fourth of twenty be?
Zarrin [17]

Answer:

The fourth of twenty is 5

Step-by-step explanation:

The 4th of twenty implies that we divide the number twenty into 4 place, let's us divide it 4

20/4= 5

This problem bothers on on division of numbers and it requires proper understanding of words/terms associated with it.

5 0
3 years ago
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