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Sophie [7]
2 years ago
13

Jasmine got a prepaid debit card with $25 on it. For her first purchase with the card, she bought some bulk ribbon at a craft st

ore. The price of the ribbon was 23 cents per yard. If after that purchase there was 19.71 left on the card, how many yards of ribbon did jasmine buy?
Mathematics
1 answer:
Umnica [9.8K]2 years ago
3 0

Answer:

23 Yards

Step-by-step explanation:

So for this question, we would have to start off with writing an equation: 19.71+0.23x=25 once we subtract 19.71 on both sides, the left over sum of money will be 5.29. Since we are dealing with BOTH Dollars and Cents, it should be remembered to use 23 CENTS instead of Dollars. \frac{5.29}{0.23}= 23 so the finals answer is 23 yards.

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Step-by-step explanation:

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3 0
3 years ago
The gym has a total of 25 treadmills and stationary bikes. there are seven more stationary bikes than treadmills.
Rudik [331]

The system of equations is t+b=25\\b=t+7

Step-by-step explanation:

We can answer this question as follows.

First of all, we call:

t = number of treadmills

b = number of stationary bikes

The two conditions that we have can be translated into equations as follows:

- The gym has a total of 25 treadmills and stationary bikes:

t+b=25

- There are seven more stationary bikes than treadmills:

b=t+7

So the system of equations to solve is

t+b=25\\b=t+7

We now solve it in the following way: first, we rewrite the second equation by bringing t on the left side,

t+b=25\\b-t=7

Now we add the 1st equation to the 2nd equation:

(t+b)+(b-t)=25+7\\t+b+b-t=32\\2b=32\\b=\frac{32}{2}=16

And therefore,

t+b=25\\t+16=25\\t=25-16=9

So, there are 16 stationary bikes and 9 treadmills.

Learn more about systems of equations:

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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9514 1404 393

Answer:

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Step-by-step explanation:

The first step is to recognize that the equation describes a vertical line in problem 3 and a horizontal line in problem 5. The perpendicular to a vertical line is a horizontal line, and vice versa.

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3. To make the desired horizontal line go through the point (-8, -1) the y-value of the line must match that of the point:

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3 years ago
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