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2 years ago

What is the distance between (-3, 4) and (-3, 10)?

Mathematics

1 answer:

xxTIMURxx [149]2 years ago

5 0

Answer:

6 is the the distance between the points

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What is the perimeter of a triangle with vertices of (5,1) (-3,3) (-7,-3)

timurjin [86]

$Vertices:\\
A(5,1)\\B(-3,3)\\C(-7,-3)\\\\ You\ must\ find\ length\ of\ AB,\ BC,\ AC.\\\\
A(5,1)\ \ \ \ \ \ B(-3,3)\\\\Distance\ between\ A \ and\ B:\\AB=\sqrt{(x_B-x_A)^2+(y_A-y_B)^2}\\\\AB=\sqrt{(-3-5)^2+(3-1)^2}\\AB=\sqrt{8^2+2^2}\\AB=\sqrt{64+4}\\AB=\sqrt{68}
$ $
 B(-3,3)\ \ \ \ C(-7,-3)\\\\Distance\ between\ B \ and\ C:\\BC=\sqrt{(x_C-x_B)^2+(y_C-y_B)^2}\\\\BC=\sqrt{(-7-(-3))^2+(-3-3)^2}\\BC=\sqrt{(-4)^2+(-6)^2}\\BC=\sqrt{16+36}\\BC=\sqrt{52}$ $A(5,1)\ \ \ \ \ \ C(-7,-3)\\\\Distance\ between\ A \ and\ C:\\AC=\sqrt{(x_C-x_A)^2+(y_C-y_A)^2}\\\\AC=\sqrt{(-7-5)^2+(-3-1)^2}\\AC=\sqrt{(-12)^2+(-4)^2}\\AC=\sqrt{144+16}\\AC=\sqrt{160}$ $Perimeter\ of\ triangle=\ AB+AC+BC=\\\sqrt{68}+\sqrt{52}+\sqrt{160}=2\sqrt{17}+2\sqrt{13}+2\sqrt{40}$

5 0

2 years ago

320% of 69 is what number?

DENIUS [597]

Answer:

220.8

Step-by-step explanation:

I believe 220.8

sorry if I am wrong.

3 0

2 years ago

Read 2 more answers

Will give Brainly

g100num [7]

Answer: 33.3%

s Step-by-step explanation: The combined arc length of the red area is 120, which is 1/3 of 360, the full arc. So the probability is 1/3, or 33.3%. Hope this helps!

6 0

2 years ago

15x+2y>20<br> i need to change this to slope intercept form, please show steps!!

aleksandrvk [35]

Answer:

y>-15/2x+10

Step-by-step explanation:

15x+2y>20

First step: Move the 15x to the other side by subtracting on both sides. 2y>-15x+20

Second step: Divide everything by 2. y>-15/2x+10

3 0

2 years ago

Solve |x+2| >5-(x-1)^2 by graphing

Anna35 [415]

Answer:

−

Step-by-step explanation:

7 0

2 years ago