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pav-90 [236]
3 years ago
11

Point M (-3, 5) is translated using this rule. (x, y) ----> (x - 1, y) What are the coordinates of M'?

Mathematics
1 answer:
Nuetrik [128]3 years ago
5 0

Answer:

The coordinates of point M' are M'(x,y) = (-4, 5).

Step-by-step explanation:

According to the statement, we have the following translation rule:

M'(x,y) = M(x,y) + (-1, 0) (1)

Where:

M(x,y) - Original point.

M'(x,y) - Translated point.

(-1, 0) - Translation vector.

If we know that M(x,y) = (-3, 5), then the coordinates of the point M' are:

M'(x,y) = (-3,5) + (-1,0)

M'(x,y) = (-4, 5)

The coordinates of point M' are M'(x,y) = (-4, 5).

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There were 900 students enrolled in a high school in 2009 and 1,500 students enrolled in the same high school in 2012. The stude
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Answer:

(A)

(t_0,P_0)=(0,900)

(t_1,P_1)=(3,1500)

(B)

m=200

(C)

P=200t+900

(D)

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Step-by-step explanation:

Let's assume time starts since 2009

so, In 2009 , t=0

P=900

In 2012,

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(A)

So, we have points as

(t_0,P_0)=(0,900)

(t_1,P_1)=(3,1500)

(B)

we can use slope formula

m=\frac{P_2-P_2}{t_2-t_1}

we can plug values

m=\frac{1500-900}{3-0}

m=200

we know that

slope is rate of change of P with respect to time

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(C)

we can use point slope form of line

y-y_1=m(x-x_1)

m=200

(t_0,P_0)=(0,900)

P-900=200(t-0)

P=200t+900

(D)

In 2017 ,

t=2017-2009=8

we can plug t=8

and we get

P=200(8)+900

P=2500

The high school's enrollment in 2017 is 2500

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