All categories

4 years ago

A 70° arc of a circle has a length of 51cm. What is the radius of the circle

Mathematics

1 answer:

Karo-lina-s [1.5K]4 years ago

8 0

The radius of circle is 41.76 cm

Solution:

Given that, 70° arc of a circle has a length of 51 cm

To find: Radius of circle

The formula for arc length when angle given in degrees is:

$Arc\ Length = 2 \pi r \times \frac{\theta}{360}$

Where,

"r" is the radius of circle and $\theta$ is the central angle in radians

From given,

Arc length = 51 cm

$\theta$ = 70 degrees

Substituting the values in formula,

$51 = 2 \times 3.14 \times r \times \frac{70}{360}\\\\51 = 6.28 \times r \times 0.194\\\\51 = 1.2211r\\\\r = \frac{51}{1.2211}\\\\r = 41.76$

Thus the radius of circle is 41.76 cm

You might be interested in

Is the binomial a factor of the polynomial nominal function?

Sedbober [7]

The factors for given equation f(x)= $x^{3} +3x^{2} -25x-75$ .

(x-1) - No
(x-3) - No
(x+3) - Yes
(x-5) - Yes
(x+5) - Yes

Step-by-step explanation:

The given equation is f(x)= $x^{3} +3x^{2} -25x-75$ .

Add 0 at the end of the equation.

$x^{3} +3x^{2} -25x-75$ = 0.

Let us group the given equation,

$(x^{3} +3x^{2}) -(25x-75)$ =0.

⇒ Group 1: $x^{3} +3x^{2}$ .

Group 2: $- 25x +75$ .

Pull out factor from each group,

⇒ Group 1: $(x+3)(x^{2})$ .

Group 2: (x+3) (-25).

Join the two group since both (x+3) is common in both groups.

$(x+3)(x^{2} -25)$ =0.

One of the factor is (x+3).

Other factors are solved by the formula, $a^{2}-b^{2} = (a+b) (a-b)$ .

$(x+3)(x^{2} -25)$ = (x+5) (x-5) .

The other factors are (x+5) and (x-5).

7 0

3 years ago

Which chart belong with the graph at the right?

agasfer [191]

Answer:

Chart nº 2

Step-by-step explanation:

Just match each points you will see which one is actually on the diagram!

6 0

3 years ago

The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

3 0

3 years ago

A preschool uses 4 gallons of milk a day. How many fluids ounces of milk does a preschool use in a day?

Mars2501 [29]

A preschool uses sixty four ounces in one day.

8 0

3 years ago

Read 2 more answers

Can someone please help me out :))

ki77a [65]

Answer:

sin(T)

cos(C)

Step-by-step explanation:

sine goes up or down for angles in the circle.

cosine goes left or right for angles in the circle.

consider a circle with is center at T, and it goes through C (so, the radius is 25 = TC).

then 7 = sin(T)×25

24 = cos(T)×25

so, sin(T) = 7/25

then, sin(T) = cos(90-T)

and the angle at C = 90-T.

therefore, cos(C)=sin(T)=7/25

tan(x) = sin(x)/cos(x)

and that would lead here always to a 7/24 or 24/7 ratio.

so, no tan function is right.

5 0

3 years ago