<h2><u>Answer:</u></h2><h2>Polynomials have the domain of all Reals. Plugging any Real number into the equation will give you a value. </h2><h2>Domain = {x|x∈R}</h2><h2><u></u></h2><h2><u> Step-by-step explanation:</u></h2><h2>The range is dependent on the curve itself. The axis of symmetry for this function is</h2><h2>x = -b/2a = -1(-10)/2(1) = 10/2 = 5 </h2><h2>The vertex is F(5) = (5)2 + (-10)(5) + 21 = 21 -50 + 21 = -8</h2><h2>Since the leading coefficient is positive, the parabola opens up and the vertex (5,-8) is a local minimum. It turns out to be an absolute minimum too so the Range = {x|x∈R, x≥-8}</h2>

<h2><u>Thank you</u></h2><h2><u>sunshinemadison101</u></h2>

4 0

3 years ago

If EFH = (5x + 1)°, HFG = 62°, and EFG = (18x + 11)°, find EFH

olga55 [171]

Given:

Consider the below figure attached with this question.

∠EFH = (5x + 1)°, ∠HFG = 62°, and ∠EFG = (18x + 11)°

To find:

The measure of ∠EFH.

Solution:

From the figure it is clear that ∠EFG is divide in two parts ∠EFH and ∠HFG. So,

$\angle EFG=\angle EFH+\angle HFG$

$18x+11=(5x+1)+(62)$

$18x+11=5x+63$

Isolate variable terms.

$18x-5x=63-11$

$13x=52$

Divide both sides by 13.

$x=\dfrac{52}{13}$

$x=4$

The value of x is 4.

$\angle EFH=(5x+1)^\circ$

$\angle EFH=(5(4)+1)^\circ$

$\angle EFH=(20+1)^\circ$

$\angle EFH=21^\circ$

Therefore, the measure of ∠EFH is 21°.

8 0

3 years ago

Theater m has 25 rows with 27 seats in each row. how many of the seats were occupiedduring a certain show?(1) during the show, t

Elis [28]

1) 475
2)375
You need to multiply 25 by 27 and you get 675 then to get answer one you need to multiply 10 by 20 to get 200 the take 200 away from 675 to get 475 then do the same thing with the second problem 20x15 which is 300 the take 300 away from 675.

5 0

3 years ago