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sertanlavr [38]
3 years ago
8

The answer to know what the answer is for this question that I have

Mathematics
1 answer:
lutik1710 [3]3 years ago
4 0

Answer:

−8x^2 − 26x − 15

Step-by-step explanation:

= (4x+3)(−2x+−5)

= (4x)(−2x) + (4x)(−5) + (3)(−2x) + (3)(−5)

= −8x^2 − 20x − 6x − 15

= −8x^2 − 26x − 15

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Solve X^4=4^X assist by solving for value of x​
Anton [14]

Answer:

  x ∈ {−0.766664695962, 2, 4}

Step-by-step explanation:

The equation is a combination of polynomial and exponential functions. There are no algebraic methods for solving such an equation. Graphical and iterative methods work nicely, though.

The attached graph shows integer solutions at x=2 and x=4. There is also an irrational negative solution near x = −0.766664695962. The latter was found by using Newton's method iteration on the graphical value of -0.767.

6 0
3 years ago
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Circle B has a center at point (0, 2) and a point W on the circle at (3, 3). Which equation represents a line that is tangent to
Solnce55 [7]

According to the given information, the equation represents a line that is tangent to the circle and goes through the point W is given by:

y = -x + 6.

<h3>What is the equation of the circle?</h3>

The equation of a circle of center (x_0,y_0) and radius r is given by:

(x - x_0)^2 + (y - y_0)^2 = r^2

In this problem, we have that the center is at point (0,2), hence:

x^2 + (y - 2)^2 = r^2

It goes through point (3,3), hence:

3^2 + (3 - 2)^2 = r^2

r^2 = 10

Hence, the equation is:

x^2 + (y - 2)^2 = 10

<h3>What is the equation of the tangent line at point W?</h3>

It is given by:

y - y(0) = \frac{dy}{dx}|_{W}(x - x(0))

Applying implicit differentiation, we have that:

2x + 2y\frac{dy}{dy} = 0

\frac{dy}{dx} = -\frac{x}{y}

Point W(3,3), hence:

(x_0, y_0) = (3,3)

\frac{dy}{dx} = -\frac{3}{3} = -1

Hence the equation is:

y - 3 = -(x - 3).

y = -x + 6.

More can be learned about the equation of a tangent line at brainly.com/question/8174665

5 0
2 years ago
Find the gross pay per paycheck based on salary
BaLLatris [955]

Answer:

Where is the info so we can show you

Step-by-step explanation:

8 0
3 years ago
Triangle ABC has vertices of A(-8,8),B(6,2),C(-2,1).Find the length of the median from C in triangle e abc
jekas [21]
First find midpoint of AB and lastly find the length of midpoint and C

8 0
2 years ago
the half life of c14 is 5730 years. Suppose that wood found at an archeological excavation site contains about 35% as much C14 a
Furkat [3]

Answer:

The wood was cut approximately 8679 years ago.

Step-by-step explanation:

At first we assume that examination occured in 2020. The decay of radioactive isotopes are represented by the following ordinary differential equation:

\frac{dm}{dt} = -\frac{m}{\tau} (Eq. 1)

Where:

\frac{dm}{dt} - First derivative of mass in time, measured in miligrams per year.

\tau - Time constant, measured in years.

m - Mass of the radioactive isotope, measured in miligrams.

Now we obtain the solution of this differential equation:

\int {\frac{dm}{m} } = -\frac{1}{\tau}\int dt

\ln m = -\frac{1}{\tau} + C

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (Eq. 2)

Where:

m_{o} - Initial mass of isotope, measured in miligrams.

t - Time, measured in years.

And time is cleared within the equation:

t = -\tau \cdot \ln \left[\frac{m(t)}{m_{o}} \right]

Then, time constant can be found as a function of half-life:

\tau = \frac{t_{1/2}}{\ln 2} (Eq. 3)

If we know that t_{1/2} = 5730\,yr and \frac{m(t)}{m_{o}} = 0.35, then:

\tau = \frac{5730\,yr}{\ln 2}

\tau \approx 8266.643\,yr

t = -(8266.643\,yr)\cdot \ln 0.35

t \approx 8678.505\,yr

The wood was cut approximately 8679 years ago.

5 0
3 years ago
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