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3 years ago

V1/V2=T1/T2. Solve for V1

1 answer:

4 0

V1=(T1/T2)*V2
In this problem, since you are given no actual numbers, the only thing you can do is multiply V2 over to get V1 alone. Since you can't cancel anything out, you are left with the answer above.

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Find the measure of arc ABC

Tomtit [17]

The answer is 360° :)

8 0

3 years ago

Read 2 more answers

The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the v

Svetllana [295]

Answer:

The differential equation becomes -

$\frac{dV}{dt} = k\sqrt[3]{V}$ i.e. $\frac{dV}{dt} = kV^{\frac{1}{3} }$

Step-by-step explanation:

Given - The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the volume.

To find - Write a differential equation that describes the relationship.

Proof -

Rate of change of volume V with respect to time t is represented by $\frac{dV}{dt}$

Now,

Given that,

The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the volume.

⇒ $\frac{dV}{dt}$ ∝ $\sqrt[3]{V}$

Now,

We know that, when we have to remove the Proportionality sign , we just put a constant sign.

Let k be any constant.

So,

The differential equation becomes -

$\frac{dV}{dt} = k\sqrt[3]{V}$ i.e. $\frac{dV}{dt} = kV^{\frac{1}{3} }$

6 0

3 years ago

A publication released the results of a study of the evolution of a certain mineral in the Earth's crust. Researchers estimate

san4es73 [151]

Answer:

a) $E(A)=\frac{1+6}{2}=3.5 ppm$

b) $P(2.875$

c) $P(X$

Step-by-step explanation:

If we work with the limits defined from 5 to 10 then part b and c from this question not makes sense. If we work with the limits 1 and 6 all the parts for the question makes sense because if we work with 5 and 10 the only thing that we can find is the expected value $E(A) = \frac{5+10}{2}= 7.5$

Assuming the following correct question : "A publication released the results of a study of the evolution of a certain mineral in the Earth's crust. Researchers estimate that the trace amount of this mineral x in reservoirs follows a uniform distribution ranging between 1 and 6 parts per million"

Solution to the problem

Let A the random variable that represent " amount of the mineral x ". And we know that the distribution of A is given by:

$A\sim Uniform(1 ,6)$

Part a

For this uniform distribution the expected value is given by $E(X) =\frac{a+b}{2}$ where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

$E(A)=\frac{1+6}{2}=3.5 ppm$

Part b

For this case we can use the cumulative distribution function for the uniform distribution given by:

$F(X=x)= \frac{x-a}{b-a} = \frac{x}{6-1} =\frac{x-1}{5} , 1 \leq X \leq 6$

And we want this probability: $P(2.875$ Part c

For this case we want this probability:

$P(X$

3 0

3 years ago

Triangle ABC is represented by the drawing below.

zhannawk [14.2K]

Step-by-step explanation:

Therefore,

(x+20) + (x-10) + (2x-30) = 180° (Sum of interior angles of a triangle)

Or, x+x+2x+20-10-30 = 180°

Or, 4x-20 = 180°

Or, 4x= 180+20

Or, 4x= 200°

Or, x= 200°/4

Therefore, x= 50°

So,

(x+20)

= 50+20

=70°

(x-10)

= 50-10

40°

(2x-30)

= 2×50-30

=100-30

=70°

Hope it helped, If it did, please mark it as the brainliest answer :)

3 0

4 years ago

X-3/2x-8 * x^2-16/x2-9

maw [93]

The answer is -x/2-8x^2-16/x^2-9.

Hope this helped.

8 0

3 years ago