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Mathematics

2 answers:

laila [671]3 years ago

7 0

Answer:

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Step-by-step explanation:

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lana66690 [7]3 years ago

4 0

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What is the slope of the line whose equation is y-4=5/2(x-2)

bezimeni [28]

Answer:

m=5/2

Step-by-step explanation:

To find the slope, use the formula y=mx+b. m is the slope. The line with the equation y-4=5/2(x-2) gives us a slope of m=5/2. Hope it helps!

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3 years ago

This is pretty easy :0

maksim [4K]

Answer:

1, 1.5, -1 1/5

Step-by-step explanation:

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3 years ago

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What is the maximum amount of baggage that may be loaded aboard the airplane for the cg to remain within the moment envelope? we

Korvikt [17]

<span>You are to find the maximum amount of baggage that may be loaded aboard the airplane for the cg (center of gravity) to remain within the moment envelope.

In order to solve this, there is a graph that shows the load weight and the load moment of pilot and front passenger, fuel, rear passenger and passenger including the baggage. Using the given data such as pilot and front passenger 250, the load moment is 9 lbs/in, for the rear passenger at 400lbs, the load moment is 28.5 lbs/in, the fuel at 30 gal has a load moment of 2 lbs/in and oil at 8 quarters is 15 lbs. The total weight is 1,350 + 250 + 400 + 15 is 2015 lbs.</span>

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3 years ago

6) the circular base of a hemisphere of radius 2 rests on the base of a square pyramid of height 6. the hemisphere is tangent to

Rasek [7]

The length of the square base is thus $2 x 3\sqrt{2}/2 = 3\sqrt{2}$ = A

<h3>What is hemisphere?</h3>

Consequently, a hemisphere is a 3D geometric object that is made up of half of a sphere, with one side being flat and the other being a bowl-like shape. It is created by precisely cutting a spherical along its diameter, leaving behind two identical hemispheres.

EXPLANATION; Let ABCDE be the pyramid with ABCD as the square base. Let O and M be the center of square ABCD and the midpoint of side AB respectively. Lastly, let the hemisphere be tangent to the triangular face ABE at P.

Notice that triangle EOM has a right angle at O. Since the hemisphere is tangent to the triangular face ABE at P, angle EPO is also 90 degree. Hence, triangle EOM is similar to triangle EPO.

OM/2 = 6/EP

OM = 6/EP x 2

OM = $6\sqrt{6^2 - 2^2} x 2 = 3\sqrt{2}/2}$