step 1
find the slope AB
A = (-3, -1) and B = (4, 4)
m=(y2-y1)/(x2-x1)------> m=(4+1)/(4+3)------> m=5/7
step 2
find the slope mBC
we know that
if two lines are perpendicular
then
the product of their slopes is equal to -1
so
mAB*mBC=-1-------> mBC=-1/mAB-----> -1/(5/7)-----> mBC=-7/5
step 3
with mBC and the point B = (4, 4) find the equation of the line BC
y-y1=m*(x-x1)-----> y-4=(-7/5)*(x-4)-----> y=-(7/5)*x+(28/5)+4---> y=-(7/5)*x+(48/5)
y=-1.4*x+9.6
therefore
the answer is
the equation of the line BC is
y=-1.4*x+9.6
see the attached figure
Answer:
(x + 8)(x + 2)
Step-by-step explanation:
x² + 10x + 16
x² + 8x + 2x + 16
x(x + 8) + 2(x + 8)
(x + 8)(x + 2)
Exponential decay is the answer
Answer:
slope = 4
y intercept = -4
y = 4x-4
Step-by-step explanation:
The y intercept is -4
The slope is (0,-4) and (1,0)
m = (y2-y1)/(x2-x1)
= (0--4)/(1-0)
= (0+4)/(1-0)
= 4/1
=4
The slope intercept equation is
y= mx+b where m is the slope and b is the y intercept
y = 4x-4