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Molodets [167]
3 years ago
14

The shock absorbers in a car act as a big spring with k=38700 N/m. When a kid gets in, the spring stretches 0.00884 m. What is t

he weight of the kid?
(Unit = N)
Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
8 0

Answer:342.108

Step-by-step explanation:

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What is 35-14+27 i really need help pls anser fast
zhuklara [117]

Answer:

<em>B is the correct answer</em>, The first choice (which you chose) is the incorrect answer.

Step-by-step explanation:

6 0
2 years ago
(20 x 40) x 14 = ?
fredd [130]

To solve this problem, we must use the order of operations outlined by PEMDAS, which tells us that we should simplify or compute parentheses first, then exponents, multiplication, division, addition, and finally subtraction.

Using this method, we have to perform the multiplication inside the parentheses first.

(20 * 40) * 14

800 * 14

Finally, we must perform the final operation to simplify this expression, which is multiplication.

800 * 14 = 11200

Therefore, your final answer is 11200.

Hope this helps!

3 0
3 years ago
Read 2 more answers
The distributive property can be applied to which expression to factor 12x3 – 9x2 + 4x – 3?
Arturiano [62]

Answer:

(4x - 3)(3x² + 1)

Step-by-step explanation:

Given

12x³ - 9x² + 4x - 3 ( factor the first/second and third/fourth terms )

= 3x²(4x - 3) + 1(4x - 3) ← factor out (4x - 3) from each term

= (4x - 3)(3x² + 1) ← in factored form

8 0
3 years ago
For the equation below, determine its order. Name the independent variable, the dependent variable, and any parameters in the eq
PIT_PIT [208]

Answer:

The equation is an differential equation of second order.

The dependent variable is x, while t is the independent variable.

Step-by-step explanation:

The order of the equation depends on the greatest grade of the derivative, in this case it's the second derivative (x'')

Since x is a function of t, we would have that t is the independent variable while x is the dependent variable.

3 0
3 years ago
Limit   
STatiana [176]

Rationalize the numerator:

\dfrac{\sqrt{x+4}-2}x\cdot\dfrac{\sqrt{x+4}+2}{\sqrt{x+4}+2}=\dfrac{(\sqrt{x+4})^2-2^2}{x(\sqrt{x+4}+2)}=\dfrac x{x(\sqrt{x+4}+2)}=\dfrac1{\sqrt{x+4}+2}

This is continuous at x=0, so we can evaluate the limit directly by substitution:

\displaystyle\lim_{x\to0}\frac{\sqrt{x+4}-2}x=\lim_{x\to0}\frac1{\sqrt{x+4}+2}=\frac1{\sqrt4+2}=\frac14

5 0
3 years ago
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