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2 years ago

(-7.5) + (-5.3) (-1.9)

Mathematics

1 answer:

Lisa [10]2 years ago

6 0

Answer:

2.57

Step-by-step explanation:

You first have to multiply the -5.3 times the -1.9. Once you do that, you get 10.07. Then, you add the -7.5.

Here are the equation steps:

(-7.5) + (-5.3)x(-1.9)

(-7.5) + (10.07)

2.57

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A particular sale involves four items randomly selected from a large lot that is known to contain 9% defectives. Let X denote th

umka2103 [35]

Answer:

The expected repair cost is $3.73.

Step-by-step explanation:

The random variable X is defined as the number of defectives among the 4 items sold.

The probability of a large lot of items containing defectives is, p = 0.09.

An item is defective irrespective of the others.

The random variable X follows a Binomial distribution with parameters n = 9 and p = 0.09.

The repair cost of the item is given by:

$C=3X^{2}+X+2$

Compute the expected cost of repair as follows:

$E(C)=E(3X^{2}+X+2)$

$=3E(X^{2})+E(X)+2$

Compute the expected value of X as follows:

$E(X)=np$

$=4\times 0.09\\=0.36$

The expected value of X is 0.36.

Compute the variance of X as follows:

$V(X)=np(1-p)$

$=4\times 0.09\times 0.91\\=0.3276\\$

The variance of X is 0.3276.

The variance can also be computed using the formula:

$V(X)=E(Y^{2})-(E(Y))^{2}$

Then the formula of $E(Y^{2})$ is:

$E(Y^{2})=V(X)+(E(Y))^{2}$

Compute the value of $E(Y^{2})$ as follows:

$E(Y^{2})=V(X)+(E(Y))^{2}$

$=0.3276+(0.36)^{2}\\=0.4572$

The expected repair cost is:

$E(C)=3E(X^{2})+E(X)+2$

$=(3\times 0.4572)+0.36+2\\=3.7316\\\approx 3.73$

Thus, the expected repair cost is $3.73.

4 0

2 years ago

What is 14100/3.6 as a whole number

malfutka [58]

Answer:

3916.6

Step-by-step explanation:

8 0

2 years ago

One number is 6 more than anouther number. the sum of their squares is 90

Flura [38]

Let x = greater number
      y = smaller number

(1) $x = y + 6
$
(1) $y = x-6$

(2) $x^{2} + y^{2} = 90$
We'll substitute y in (1) to (2)
(2) $x^{2} + (x-6)^{2} = 90$
   $x^{2} + (x^{2} - 12x + 36) = 90$
   $x^2 + x^2 -12x + 36 - 90 = 0$
   $2x^2 - 12x -54 = 0
$
   $2(x^2 - 6x - 27) = 0$
   $2(x - 9)(x + 3) = 0$
x - 9 = 0 or x + 3 = 0
      x = 9 x = -3
and
y = x - 6 y = x - 6
y = 9 - 6 y = -3 - 6
y = 3 y = -9

Therefore, the two numbers can be 9 and 3 or -3 and -9.

6 0

2 years ago

Samantha correctly answered 38 out of 55 questions on a test. She must score 70% or greater to pass the test.

Arada [10]

Divide given over total and multply by 100 to get a percent

so correct answers/ total answer * 100 = score

38 / 55 * 100 = 69% so she failed oppppppssss

8 0

2 years ago

Read 2 more answers

(x^3-3x^2+x-8)/(x-1)

nalin [4]

Answer:

3-3x^2+x-8)/(x-1)

Step-by-step explanation:

3-3x^2+x-8)/(x-1)

7 0

1 year ago