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Alex17521 [72]
4 years ago
9

Find the area of each 4 sides

Mathematics
2 answers:
alexdok [17]4 years ago
7 0
Square because you said 4 sides
11Alexandr11 [23.1K]4 years ago
7 0
If A=BH, then B= 5.5 and H= 3.3. Therefore, multiply 5.5 x 3.3 and you get 18.15.
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The quotient of 20 and a number will be 10​
Dimas [21]

Answer:

2

Step-by-step explanation:

lets think of the missing number as x so any number times 10 should equal 20 so x=2

and your equation should look like this--------> 20÷2=10

7 0
3 years ago
1.The mass of an object, usually measured in kilograms and grams is?
Marat540 [252]

Answer:

1.kg(not sure)

2. mass

7 0
3 years ago
Read 2 more answers
SOMEBODY PLEASE HELP MEEEEEEEE
Igoryamba

Answer To Number 3:

No. This is not a function.

Step-by-step explanation:

This is not a function, because you cannot have 2 inputs(x) that are the same number, but you can have 2+outputs(y) that are the same number.

5 0
3 years ago
A cylinder vase has a height of 10 inches and a diameter of 3 inches. If the water raises to 9/10 of the way to the top, approxi
goblinko [34]

Answer:

The volume of water in the vase is 64 in^3

Step-by-step explanation:

A cylinder vase has a height, h, of 10 inches and its diameter of 3 inches. This means that its radius, r, is:

r = 3 / 2 = 1.5 inches

To find the volume of the water in the vase if the water raises to 9/10 of the way to the top, we first have to find the volume of the vase when it is filled with water and then, find 9/10 of that volume.

The volume of a cylinder is given as:

V = \pi r^2h

The volume of the vase will be:

V = \pi * 1.5^2 * 10\\V = 70.69 in^3

Hence, the volume of the water in the vase when it is 9/10 filled is:

\frac{9}{10} * 70.69 = 63.62 in^3

Approximating to the nearest cubic inch, the volume of water in the vase is 64 in^3

5 0
3 years ago
What is the surface area of the pyramid formed from the net shown here? The triangles are equilateral, and each triangle has a h
Finger [1]

Answer:

62.4

Step-by-step explanation:

62.4

8 0
3 years ago
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