The equation of the circle:
![(x-a)^2+(y-b)^2=r^2](https://tex.z-dn.net/?f=%28x-a%29%5E2%2B%28y-b%29%5E2%3Dr%5E2)
where:
(a; b) - coordinates of the center
r - a radius
Use:
![(a\pm b)^2=a^2\pm2ab+b^2\ \ \ \ (*)](https://tex.z-dn.net/?f=%28a%5Cpm%20b%29%5E2%3Da%5E2%5Cpm2ab%2Bb%5E2%5C%20%5C%20%5C%20%5C%20%28%2A%29)
We have:
Answer:The center: (-2; 4)The radius: r = 4
60=4x+24
-24. -24
36=4x
36÷4
x= 9
she needs babysit 9 more hours to have enough for the bool series
-sqrt(y) = -5
Multiply
each side by (-) negative sign: sqrt(y) = 5
Square each
side: y = 25
Answer: (C) 25
M.N and O are 60 degree. And you have to know that 30 60 and 90 triangle. if 30 degrees opposite is measuring A , 60 is A square root 3 and the 90's opposite is being 2A. So 90 degree opposite is 16 square root 3 and 30 degree is being 8 square root 3 and 60 is
![8 \sqrt{3} \times \sqrt{3} = 24](https://tex.z-dn.net/?f=8%20%5Csqrt%7B3%7D%20%20%5Ctimes%20%20%5Csqrt%7B3%7D%20%20%3D%2024)
the height is 24 .
first polygon
ext. angle=180°-120°
=60°
![ext \: ang = \frac{360}{n}](https://tex.z-dn.net/?f=ext%20%5C%3A%20ang%20%3D%20%20%5Cfrac%7B360%7D%7Bn%7D%20)
n=360°/60°
n=6
second polygon
n=2(6)=12
ext. ang= 360°/n = 360°/12° = 30°
int. ang = 180°-30°= 150°
answer is C