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noname [10]
3 years ago
10

Select all the values that cannot be probabilities a. 3/5b. 1c. -0.45d. 0.06e. 1.16f. 0g. 5/3h. √2

Mathematics
1 answer:
nikitadnepr [17]3 years ago
4 0

Answer:

c,-0.45 ,

e. 1.16

g. 5/3

h. √2

Cannot be probability.

Step-by-step explanation:

Probability of any occurrence is always in the interval of 0 to 1. 0 and 1 inclusive.

0≤P(A)≤1

Any value outside this boundaries cannot be probability.

Therefore, -0.45,1.16,5/3 and √2 cannot be probability.

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Step-by-step explanation:

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nA car dealer who sells only late-model luxury cars recently hired a new salesperson and believes that this salesperson is selli
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Answer:

The value of an appropriate test statistic for the car dealer to use is -4.

Step-by-step explanation:

The null hypothesis is:

H_{0} = 4600

The alternate hypotesis is:

H_{1} < 4600

The test statistic is:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

In this problem:

X = 4100, \mu = 4600, \sigma = 500, n = 16

Then

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

t = \frac{4100 - 4600}{\frac{500}{\sqrt{16}}}

t = -4

The value of an appropriate test statistic for the car dealer to use is -4.

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PLEASE HELP <br> The value of which of these expressions is closest to e?
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The total of 3 suitcases is 127 lb. The gray suitcase weighs 11 lb more than the pink suitcase. The pink suitcase weighs 5 lb th
Gnoma [55]

If the gray suitcase weighs 11 lb more than the pink suitcase, the pink suitcase weighs 5 lb than the blue suitcase, and the total of 3 suitcases is 127 lb, then the blue suitcase weighs 35.3 lb

Let the gray suitcase be represented by g

Let the pink suitcase be represented by p

Let the blue suitcase be represented by b

The gray suitcase weighs 11 lb more than the pink suitcase

g    =   p   +   11........(1)

The pink suitcase weighs 5 lb than the blue suitcase.

p   =  b  +  5

b  =  p  -  5...........(2)

Total of 3 suitcases = 127 lb

p  +  b  +  g    =  127............(3)

Substitute equations (1) and (2) into equation (3)

p  +  p  - 5 + p  +  11   =  127

3p  +  6   =  127

3p   =  127  -  6

3p   =  121

p  =  121/3

p  = 40.3 lb

Substitute p = 40.3 into equation (2)

b = p - 5

b  = 40.3  - 5

b  =  35.3

The blue suitcase weigh 35.3 lb

Learn more here: brainly.com/question/11865047

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