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Dima020 [189]
3 years ago
7

What is the conjugate base in the following equation: HBr + H2 O \longrightarrow ⟶ H3 O+ + Br-

Chemistry
1 answer:
kolbaska11 [484]3 years ago
7 0

Answer:

\rm Br^{-} would be the conjugate base in this reaction according to the Bronsted-Lowry acid-and-base theory.

Explanation:

Among the reactants, the Bronsted-Lowry acid is the species that supplies protons \rm H^+. The Bronsted-Lowry base would be the species that accept the protons.

On the product side of the equation, the BL-acid donates a proton \rm H^+ to produce the conjugate base. The BL-base accepts a proton \rm H^+ to produce the conjugate acid.

In this case, each \rm HBr molecule donates a proton to form one \rm Br^{-} ion. Hence,

Each \rm H_2O molecule would accept a proton to produce an \rm H_3O^{+} ion. Hence,

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What is the rate law for the uncatalyzed reaction?
elena55 [62]

What is the rate law for the uncatalyzed reaction?

Metals often form several cations with different charges. Cerium, for example, forms and ions, and thallium forms and ions. Cerium and thallium ions react as follows:  

2Ce^4+(aq) + Tl^+(aq) ---> 2Ce^3+(aq)+Tl^3+(aq)  

This reaction is very slow and is thought to occur in a single elementary step. The reaction is catalyzed by the addition of Mn^2+ according to the following mechanism:  

Ce^4+(aq)+Mn^2+(aq) ---> Ce^3+(aq)+Mn^3+(aq)  

Ce^4+(aq)+Mn^3+(aq) ---> Ce^3+ (aq) + Mn^4+ (aq)  

Mn^4+(aq) + Tl^+(aq) ---> Mn^2+(aq) + Tl^3+(aq)  

If the uncatalyzed reaction occurs in a single elementary step, why is it a slow reaction?  

1)The probability of an effective three-particle collision is low.  

2) The transition state is low in energy.  

3) The reaction requires the collision of three particles with the correct energy and orientation.  

4) All reactions that occur in one step are slow.  

The catalyzed reaction is first order in [Ce^4+] and first order in [Mn^2+]. Which of the steps in the catalyzed mechanism is rate determining?  

Based on their available oxidation states, rank the following metals on their ability to catalyze this and other oxidation-reduction reactions.  

Rank from best to worst catalyst.  

Vanadium, titanium, manganese

4 0
4 years ago
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Macbeth informs his wife that
faust18 [17]
The answer is B hope it helped

3 0
3 years ago
If 20 mL of gas is subjected to a temperature change from 10°C to 100°C and a pressure change from 1 atm to 10 atm,
Evgesh-ka [11]

Answer:

E. None of these

Explanation:

We know, By GAS laws,

PV = NRT, where p- pressure, v- volume, n- number of moles, R- gas constant ,and T- temperature

Now, In the question, the number of moles remains the same as the gas is the same. so n is constant so we can compare n before and after a temperature change.

\frac{P1V1}{RT1} = \frac{P2V2}{RT2}

where P1= 1 atm, P2 = 10 atm, V1= 20 mL, T1= 10°C and T2= 100°C

We don't have to worry about the standard units as they are present equally on both the sides and get cut, same goes for R( gas constant)

So putting values, we get

\frac{1*20}{R*10} = \frac{10*V2}{R*100}

Cutting, R on both sides and moving contents to the right so that only V2 is left on the left.

\frac{1*20*100}{10*10} = V2

∴ V2 = \frac{2000}{100}

∴ V2 = 20mL

3 0
2 years ago
(1)List three things you know about<br> an atom? (2) What is matter created of?
kicyunya [14]

Answer:

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Explanation:

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mrs_skeptik [129]

You can see my previous answer to this very same question on brainly.com/question/11374210.


The answer is:  option D. Response to environment.


Explanation:


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Such behavior is named tropism. Tropism may be positive or negative.


When the plant's stem bends toward the window, it is showing positive phototropism, which means that the plant growth response to light such that the stems bend toward light, permiting the leaves to receive more light.


I also mention that while the plant's stems posses positive phototropism they posses negative gravitropism and the roots posses positive gravitropism.


Gravitropism is the response of the plant growth to gravity.


Stems grow away from gravity meaning that this is negative gravitropism, but roots grow toward gravity which is positive gravitropism

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