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sineoko [7]
4 years ago
10

The researcher performed a follow-up experiment to measure the rate of oxygen consumption by muscle and brain cells. Predict the

effect of the MT - ND5 mutation on the rate of oxygen consumption in muscle and brain cells. Justify your prediction. The researcher had hypothesized that the addition of the vitamin that is similar in structure to NADH would increase the activity of the mutated NADH dehydrogenase enzyme in individuals with the disorder. Explain how the vitamin most likely increased the activity of the enzyme.
Chemistry
2 answers:
Naddik [55]4 years ago
0 0

Answer:

Mitochondria are abundantly present in mammalian cells. Their fraction varies from tissue to tissue, ranging from <1% (volume) in white blood cells to 35% in heart muscle cells. However, mitochondria should not be thought of as single entities, but rather a dynamic network that continuously undergoes fission and fusion processes. In skeletal muscle, mitochondria exist as a reticular membrane network. The subsarcolemmal (SS) and intermyofibrillar (IMF) mitochondria are located in distinct subcellular regions, and they possess subtle differences in biochemical and functional properties that are characterized by their anatomical locations. SS mitochondria lie directly beneath the sarcolemmal membrane and the IMF mitochondria are located in close contact with the myofibril. Their different properties are likely to influence their capacity for adaptation. SS mitochondria account for 10-15% of the mitochondrial volume and this population has been shown to be more susceptible to adaptation than the IMF mitochondria. However, the IMF mitochondria were found to have higher rates of protein synthesises, enzyme activities and respiration (1).

Explanation:

uranmaximum [27]4 years ago
0 0

Answer:

The rate of oxygen consumption by muscle and brain cells will decrease. The MT-ND5 mutation causes a buildup of lactic acid which occurs as a result of glycolysis not entering the Krebs cycle and instead entering fermentation. Because it is not entering the krebs cycle, there is no oxygen being consumed.

Explanation:

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Please show all work for full credit.
koban [17]

Answer:

No, it is not sufficient

Please find the workings below

Explanation:

Using E = hf

Where;

E = energy of a photon (J)

h = Planck's constant (6.626 × 10^-34 J/s)

f = frequency

However, λ = v/f

f = v/λ

Where; λ = wavelength of light = 325nm = 325 × 10^-9m

v = speed of light (3 × 10^8 m/s)

Hence, E = hv/λ

E = 6.626 × 10^-34 × 3 × 10^8 ÷ 325 × 10^-9

E = 19.878 × 10^-26 ÷ 325 × 10^-9

E = 19.878/325 × 10^ (-26+9)

E = 0.061 × 10^-17

E = 6.1 × 10^-19J

Next, we work out the energy required to dissociate 1 mole of N=N. Since the bond energy is 418 kJ/mol.

E = 418 × 10³ ÷ 6.022 × 10^23

E = 69.412 × 10^(3-23)

E = 69.412 × 10^-20

E = 6.9412 × 10^-19J

6.9412 × 10^-19J is required to break one mole of N=N bond.

Based on the workings above, the photon, which has an energy of 6.1 × 10^-19J is not sufficient to break a N=N bond that has an energy of 6.9412 × 10^-19J

8 0
3 years ago
A laboratory technician combined sodium hydroxide with excess iron(II) nitrate. A reaction took place according to this chemical
Whitepunk [10]

 The initial  mass  of sodium hydroxide  is  3.3 g (answer C)

 <u><em>calculation</em></u>

Step 1 : find the  moles of iron (ii) hydroxide (  Fe(OH)₂

moles =  mass÷  molar mass

from periodic table the  molar mass of Fe(OH)₂  = 56 + [16 +1]2  = 90 g/mol

moles  is therefore = 3.70 g÷ 90 g/mol = 0.041 moles

Step 2:  use the mole ratio to  calculate the moles of  sodium hydroxide (NaOH)

   from given equation  NaOH : Fe(OH)₂    is 2 :1

therefore the moles of NaOH = 0.041 x 2 = 0.082 moles

Step 3: find  mass of NaOH

mass = moles x molar mass

from the periodic table the  molar mass of NaOH = 23 +16 +1  = 40 g/mol

mass  = 0.082  moles x 40 g/mol = 3.3 g ( answer C)


8 0
3 years ago
What is the current produced when a 12-Volt battery encounters a resistance of 20 Ohms?
Verdich [7]

Answer:

Explanation:

V = IR

I = V/R

I = (12V)/(20Ω)

I = 0.6 A

4 0
3 years ago
Which has a greater volume, 10 grams of water or 10 grams of acetone?
WINSTONCH [101]

Density is defined as the ratio of mass to the volume.

Density = \frac{Mass}{Volume}          (1)

Mass of water = 10 grams

Mass of acetone  = 10 grams

Density of water  = 1 \frac{g}{cm^{3}}

Density of acetone  = 0.7857 \frac{g}{cm^{3}}

Put the value of density of water and its mass in equation (1)

1 \frac{g}{cm^{3}} =  \frac{10 g}{volume}

Volume of water =  10 cm^{3}

Put the value of density of acetone and its mass in equation (1)

0.7857 \frac{g}{cm^{3}} =  \frac{10 g}{volume}

Volume of acetone = 12.72 cm^{3}

Thus, volume of acetone is more than volume of water because the density of acetone is lower.

6 0
3 years ago
What are the concentrations of h3o+ and oh− in tomatoes that have a ph of 4.10?
IRINA_888 [86]

Answer : The concentration of H_3O^+ and OH^- are 7.94\times 10^{-5} and 1.258\times 10^{-10} respectively.

Solution : Given,

pH = 4.10

pH : pH is defined as the negative logarithm of hydronium ion concentration.

Formula used : pH=-log[H_3O^+]

First we have to calculate the hydronium ion concentration by using pH formula.

4.10=-log[H_3O^+]

[H_3O^+]=antilog(-4.10)

[H_3O^+]=7.94\times 10^{-5}

Now we have to calculate the pOH.

As we know, pH+pOH=14

4.10+pOH=14

pOH=9.9

Now we have to calculate the hydroxide ion concentration.

pOH=-log[OH^-]

9.9=-log[OH^-]

[OH^-]=antilog(-9.9)

[OH^-]=1.258\times 10^{-10}

Therefore, the concentration of H_3O^+ and OH^- are 7.94\times 10^{-5} and 1.258\times 10^{-10} respectively.

5 0
3 years ago
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