Answer:
Homopolysaccharides are polysaccharides composed of a single type of sugar monomer.
The ice structure takes up more volume than the liquid water molecules, hence ice is less dense than liquid water. What is the exact change in volume of the water when it freezes as ice? Example: Calculate the volume in a 100 g ice cube with a density of 0.92 g per mL.
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Complete Question
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Answer:
The specific heat is
Explanation:
From the question we are told that
The mass of the sample is 
The mass of the water is 
The initial temperature of the sample is 
The initial temperature of the water is 
The final temperature of the water is 
Note the final temperature of water is equal to the final temperature of brass sample
The pressure is 
Generally for according to the law of energy conservation
The heat lost by sample = The heat gain by water
The heat lost by brass sample is mathematically evaluated as
![H_L = m * c_b * [T_i - T]](https://tex.z-dn.net/?f=H_L%20%20%3D%20%20m%20%2A%20c_b%20%20%2A%20%20%5BT_i%20-%20T%5D)
Where
is the specific neat of the brass sample
The heat gained by water is mathematically evaluated as
![H_g = m_w *c_w * [T_w - T ]](https://tex.z-dn.net/?f=H_g%20%20%3D%20m_w%20%2Ac_w%20%2A%20%5BT_w%20-%20T%20%5D)
where
is the specific heat of water which has a constant value of

So
![H_L = H_g \ \equiv m* c_b * [T_i -T] = m_w * c_w * [T - T_w]](https://tex.z-dn.net/?f=H_L%20%20%3D%20%20H_g%20%5C%20%5Cequiv%20m%2A%20c_b%20%20%2A%20%5BT_i%20-T%5D%20%3D%20%20m_w%20%2A%20c_w%20%2A%20%5BT%20-%20T_w%5D)
substituting values
![52.4 * c_b * [95.1 - 17.6] = 150 * 4.186 * [ 17.6 - 15.0]](https://tex.z-dn.net/?f=52.4%20%2A%20c_b%20%20%2A%20%5B95.1%20%20-%2017.6%5D%20%3D%20%20150%20%2A%204.186%20%2A%20%5B%2017.6%20-%2015.0%5D)
