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Anna007 [38]
4 years ago
15

A supposedly silver crown is tested to determine its density. it displaces 10.7 ml of water and has a mass of 112 g. part a coul

d the crown be made of silver?
Chemistry
1 answer:
Anni [7]4 years ago
4 0

The volume of water displace by crown is 10.7 mL. This will be equal to the volume of crown. Mass of crown is 112 g.

Density of a substance is defined as mass of substance per unit volume. It is mathematically represented as follows:

d=\frac{m}{V}

Putting the values,

d=\frac{112 g}{10.7 mL}=10.46 g/mL

The theoretical value of density of silver is 10.5 g/cm^{3} also, 1 mL is equal to 1 cm^{3} thus, density will be 10.5 g/mL.

This is approximately equal to the calculated value thus, the crown is made up of silver.


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Explanation:

From the question we are told that

   The  coefficient of thermal expansion is \alpha  =  \frac{1}{V} *  (\frac{\delta V}{ \delta  P})  P

    The coefficient of compressibility is \beta  =  - (\frac{1}{V} ) *  (\frac{\delta V}{ \delta P} ) T

Generally the ideal gas is  mathematically represented as

        PV  =  nRT

=>      V  =  \frac{nRT}{P}  --- (1)

differentiating both side with respect to T at constant P

       \frac{\delta V}{\delta T }  =  \frac{ n R }{P}

substituting the equation above into \alpha

       \alpha  =  \frac{1}{V} *  ( \frac{ n R }{P})  P

        \alpha  = \frac{nR}{PV}

Recall from ideal gas equation  T =  \frac{PV}{nR}

So

          \alpha  =  \frac{1}{T}

Now differentiate equation (1) above with respect to  P  at constant T

          \frac{\delta  V}{ \delta P}  =  -\frac{nRT}{P^2}

substituting the above  equation into equation of \beta

        \beta  =  - (\frac{1}{V} ) *  (-\frac{nRT}{P^2} ) T

        \beta =\frac{ (\frac{n RT}{PV} )}{P}

Recall from ideal gas equation that

       \frac{PV}{nRT}  =  1

So

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Now  considering (\frac{ \delta P }{\delta  T} )V

From equation (1) we have that

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From  ideal equation

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So

     \frac{\delta P}{\delta  T}  =  \frac{PV}{TV}

=>  \frac{\delta  P}{\delta  T}  =  \frac{P}{T}

=>   \frac{\delta  P}{\delta  T}  =  \frac{\alpha }{\beta}

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