The solution to the given expression negative four and one third ÷ two and one fifth is -1 32/33
<h3>Fraction division</h3>
negative four and one third ÷ two and one fifth
-4 1/3 ÷ 2 1/5
= -13/3 ÷ 11/5
- Multiply by the reciprocal of 11/5
- The reciprocal of 11/5 is 5/11
= -13/3 × 5/11
= (-13 × 5) / (3 × 11)
= -65 / 33
= -1 32/33
Therefore, the solution to the fraction is -1 32/33
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The answer is a = 
Step-by-step explanation:
<em>1. Convert the mixed fraction to an improper fraction</em>
To find the numerator, multiply the denominator by the whole number and add the numerator to it.
The denominator remains the same.
So, 2
will be 
<em>2. Now the equation is,</em>
a - 
a = 
+ a
<em>3. Take LCM on both sides. </em>
For the left side, multiply the first fraction by 
and multiply the second fraction by 
a - 
a = 
<em>4. Solve by making a the subject</em>
=
=
=10+8a
= 10 + 8a
a = 2(10 + 8a)
a = 20 + 16a
a-16a = 20
-15a = 20
a = 
a =
Therefore, the answer is a =
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9514 1404 393
Answer:
₹1000
Step-by-step explanation:
Let m represent the marked price. After the discount, the price is 0.80m. After the tax is added, the price is (0.80m)(1.13). This value is Rs 904, so the marked price is ...
(0.80m)(1.3) = ₹904
m = ₹904/(0.80×1.13) = ₹904/0.904
m ≈ ₹1000
The marked price of the watch is ₹1000.
Answer:
The southwest corner of the garden will be 2 feet south and 3 feet west of the tree. A circle has a center at (3,5). What is the area of the circle to the nearest tenth of a square unit? Which of the following could be the vertices of the triangle? A garden that is 5 feet by 6 feet has a walkway that is 2 feet wide around it.
Answer:
(m³/3 + 5m/2 + 3)pi
Step-by-step explanation:
pi integral [(f(x))² - (g(x))²]
Limits 0 to 1
pi × integral [(2+mx)² - (1-mx)²]
pi × integral[4 + 4mx + m²x² - 1 + 2mx - m²x²]
pi × integral [m²x² + 5mx + 3]
pi × [m²x³/3 + 5mx²/2 + 3x]
Upper limit - lower limit
pi × [m²/3 + 5m/2 + 3]
Verification:
m = 0
[pi × 2² × 1] - [pi × 1² × 1] = 3pi
[m³/3 + 5m/2 + 3]pi
m = 0
3pi
