If a patient being treated acute hypokalemia has a drug history that include propranolol, digoxin, and warfarin, the nurse suspects what could be the causal factor of digitalis poisoning.
<h3>What is the remedy for a digitalis overdose?</h3>
Digoxin immune fab, an anti-digoxin immunoglobulin antibody, is the main treatment for digoxin toxicity. Digoxin toxicity symptoms such hyperkalemia, hemodynamic instability, and arrhythmias have been demonstrated to be extremely responsive to treatment with this antidote.
<h3>Digoxin toxicity: what causes it?</h3>
Hypokalemia, which can happen as a result of diuretic medication, is the most typical cause of digoxin poisoning. Dosing mistakes are another frequent reason for toxicity in younger people. The risk of digoxin toxicity is affected by a number of factors, such as:
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The hypothesis is that increasing the
intensity of positive visual emotional
stimuli increases amygdala activation.
This result should complement knowledge
regarding negative as well as positive
emotions in other domains (using
olfactory, auditory, gustatory or semantic
stimuli).
Answer:
The previous sentence is false.
Explanation:
The tricuspid valve is between the right atrium and right ventricle. Also,The valve which is under the most pressure to block blacflow of blood during ventricular systole is the mitral valve. Mitral valve is the one which is located between the left atrium and left ventricle.
The heart works with two processes: diastole and systole. Systole occurs when the heart contract himself to expulse blood to the vessels, and when the heart relaxes while it fulfills of blood is called diastole. During the systole process the tricuspid valve needs to be closed to allow the increase of pressures inside the heart cameras and then allow the expulse of blood. But, during diastole, tricuspid valve needs to be open to allow the correct filling of right side of the heart.
You should be compressing at about 1 1/2 inches
Answer:
0.00508368 grams
Explanation:
From the question we are told that the daily allowance for infants and children is 8.00 × 10⁻⁶ mole of copper per kiogram of body weight.
Since this value is given in moles, we have to convert it to mass
Molar mass of a compound = mass in grams / no of moles of the compound.
So, Molar mass of copper = 63.546
No of moles of copper per kg = 8.00 × 10⁻⁶ mole
63.546 = mass/ 8.00 × 10⁻⁶ mole
Cross multiply
Mass of copper per kg body weight = 8.00 × 10⁻⁶ × 63.546
= 0.000508368 grams
Hence, the daily allowance of copper required for infants or children per kg of weight = 0.000508368 grams.
For a 10 kg infant this is calculated as:
If 1 kg per weight of an Infant = 0.000508368grams
10 kg =
We cross multiply
10 kg × 0.000508368 grams
= 0.00508368 grams.
Therefore, the mass of copper required per day for a 10 kg child is 0.00508368 grams