seeing that its a 2017 it sounds pretty good.... as long as thats really what you want ( you should totally just get a dirt bike lol)
Answer:
The answer to this question is given below in the explanation section.
Explanation:
The correct answer to this question is the planning stage. Because the planning stage represents the development of documents that provide the basis for acquiring the resources and for developing the requirement document. at this stage, you plan about what you are going to develop and how to develop it. At this stage, you come out mainly with two documents i.e. project proposal and requirement document.
Other options are not correct because:
In the project management, after planning, you will start designing the product, and after designing you start developing the product, and at the implementation stage, you implement or deploy the product to the customer or to the client. The requirement document that is developed at the planning stage can be used in the later stages of the project.
Please note that the Problem to be solved from Protocol 1 is not provided hence the general answers. To construct and send, open a network environment a single multi-packet message, simply click "Add Packet" and then click "Send at Once".
<h3>How will the receiver know the order of the packets or if any are missing?</h3>
If the text or message sent does not make any reading sense, or if certain words are jumbled and out of place, then it is clear that something is wrong.
If the messages arrive in a coherent fashion, then the packet was fully received.
<h3>How will the receiver request missed packets and what will the sender do in response?</h3>
Where the users are familiar with the Transmission Control Protocol, lost packets can be detected when there is a timeout. Lost packets are referred to as Dropped packets.
Learn more about Packets at:
brainly.com/question/17777733
(A) the same, by applying styles the same formats are being applied each time.
Answer:
a) The method runs infinitely and causes a StackOverflowError.
// Return the factorial for a specified index
public static long factorial(int n)
{
if (n == 0)
return 1;
else
return n * factorial(n - 1);
}
b) Invoking factorial(2) returns 2.
// Return the factorial (2)
public static long factorial(int 2)
{
if (n == 2)
return 2;
else
return 2 * factorial(3 - 1);
}
c) Invoking factorial(1) returns 1.
// Return the factorial(1)
public static long factorial(int 1)
{
if (n == 1)
return 1;
else
return 1 * factorial(1 - 1);
}
d) Invoking factorial(0) returns 0.
// Return the factorial(0)
public static long factorial(int 0)
{
if (n == 0)
return 0;
else
return 0 * factorial(0 - 1);
}
Explanation:
