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3 years ago

What is measure of Arc AC if the m ∠BAC = 28°?

Mathematics

2 answers:

liq [111]3 years ago

8 0

14 degrees. It equals half the intercepted arc.
(See attached graphic)

mart [117]3 years ago

5 0

Answer:

C. $56^{\circ}$

Step-by-step explanation:

We have been given an image of a circle. We are asked to find the measure of arc AC.

We will use tangent-secant theorem, which states that the angle formed by a tangent to a circle and a chord is equal to half the angle measure of the intercepted arc.

Using above theorem we can set an equation to find measure of arc AC as:

$m\angle BAC=\frac{1}{2}\times \text{ Measure of arc AC}$

$28^{\circ}=\frac{1}{2}\times \text{ Measure of arc AC}$

Multiplying both sides of our equation by 2, we will get,

$2*28^{\circ}=\frac{1}{2}*2\times \text{ Measure of arc AC}$

$56^{\circ}=\text{ Measure of arc AC}$

Therefore, the measure of arc AC is 56 degrees and option C is the correct choice.

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A second number is 6 less than a first number. A third number is twice the first number. If the sum of three number is 306, find

Serga [27]

Answer:

first number = 78

second number = 72

third number = 156

Step-by-step explanation:

first number = a

second number = b

third number = c

we have

b=a-6 equation 1

c=2a equation 2

a+b+c=306 equation 3

using equation 1 and equation 2 in equation 3 we have

a+a-6+2a=306

4a=306+6

4a=312

a=312/4

a=78= first number

b=78-6=72=second number

c=2*(78)=156 third number

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3 years ago

How to show your work for 9 divided by 2.43

gizmo_the_mogwai [7]

Just do normal division, just like ignore the decimal point. for a moment once you got your answer bring back the decimal point back up to your answer. You would get 0.27 as your answer.

3 0

3 years ago

Read 2 more answers

Multiply 3/sqrt17- sqrt2 by which fraction will produce an equivalent fraction with rational denominator

zzz [600]

Answer:

Step-by-step explanation:

To simplify something that looks like $\frac{\text{whatever}}{\sqrt{a}-\sqrt{b}}$ you would multiply the top and bottom by the conjugate of the bottom. So you multiply the top and bottom for this problem I just made by:

$\sqrt{a}+\sqrt{b}$ .

If you had $\frac{\text{whatever}}{\sqrt{a}+\sqrt{b}}$ , then you would multiply top and bottom the conjugate of $\sqrt{a}+\sqrt{b}$ which is $\sqrt{a}-\sqrt{b}$ .

The conjugate of a+b is a-b.

These have a term for it because when you multiply them something special happens. The middle terms cancel so you only have to really multiply the first terms and the last terms.

Let's see:

(a+b)(a-b)

I'm going to use foil:

First: a(a)=a^2

Outer: a(-b)=-ab

Inner: b(a)=ab

Last: b(-b)=-b^2

--------------------------Adding.

a^2-b^2

See -ab+ab canceled so all you had to do was the "first" and "last" of foil.

This would get rid of square roots if a and b had them because they are being squared.

Anyways the conjugate of $\sqrt{17}-\sqrt{2}$ is