Answer:
The correct option is (A).
Step-by-step explanation:
The p-value is well-defined as per the probability, [under the null-hypothesis (H₀)], of attaining a result equivalent to or more extreme than what was the truly observed value of the test statistic.
A small p-value (typically p < 0.05) specifies strong evidence against the null hypothesis (H₀), so the null hypothesis is rejected. A p-value less than 0.05 is considered as statistically significant.
A large p-value (p > 0.05) specifies fragile proof against the H₀, so the null hypothesis is failed to be rejected.
In this case the <em>p</em>-value of the test is,
<em>p</em>-value = 0.003
And the significance level of the test was,
<em>α</em> = 0.05.
p-value = 0.003 < <em>α</em> = 0.05.
The p-value less than the significance level of the test.
Thus, the results are statistically significant.
The correct option is (A).
<h3>Answer: 10</h3>
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Explanation:
We'll start off converting each mixed number into an improper fraction.
The formula to use is 
So,

And,

So the task of computing
is exactly the same as computing 
Notice how we have an 8 up top and an 8 down below. Those 8's cancel out and we're left with
. That fraction does not reduce any further.
The last step is to convert that improper fraction result to a mixed number.

Or you could note that 17/3 leads to 5 remainder 2. The 5 is the whole part and the 2 forms the numerator of the fractional part 2/3.
The value is in
form where
Therefore, A+b+c = 5+2+3 = 10
Answer:
Numerator = 2(b^2+a^2) or equivalently 2b^2+2a^2
Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3
Step-by-step explanation:
Let
S = 2b/(b+a)^2 + 2a/(b^2-a^2) factor denominator
= 2b/(b+a)^2 + 2a/((b+a)(b-a)) factor denominators
= 1/(b+a) ( 2b/(b+a) + 2a/(b-a)) find common denominator
= 1/(b+a) ((2b*(b-a) + 2a*(b+a))/((b+a)(b-a)) expand
= 1/(b+a)(2b^2-2ab+2ab+2a^2)/((b+a)(b-a)) simplify & factor
= 2/(b+a)(b^2+a^2)/((b+a)(b-a)) simplify & rearrange
= 2(b^2+a^2)/((b+a)^2(b-a))
Numerator = 2(b^2+a^2) or equivalently 2b^2+2a^2
Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3