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il63 [147K]
3 years ago
15

Please help fastI WILL MARK YOU AS BRAINLIEST ​

Mathematics
1 answer:
VashaNatasha [74]3 years ago
4 0

Answer:

The bottom left one

Step-by-step explanation:

if they spin the spinner twice the outcomes from the first amount of outcomes doubles because it is doubling the chances

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What is the Simplify expression of (15+39)÷6
Usimov [2.4K]

Answer:

9

Step-by-step explanation:

\frac{(15 + 39)}{6}  \\  \frac{54}{6 }  \\ ans = 9 \\

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3 years ago
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Jerry drew JKL and MNP so that K= N,L= P, JK=6, and MN=18. Are JKL and MNP similar? IF so, identify the similarity postulate or
Nesterboy [21]

The right answer is similar-aa

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How do I solve this equation?
svlad2 [7]
The answer is option three(photo for step by step)

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3 years ago
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An online data base charges $25 an hour during the day and $12.50 an hour at night. If a research company paid $250 for 12 hours
Firdavs [7]

Answer

Find out the  which system of equations could be used to determine the number of hours charged at the day rate (d) and at the night rate (n) .

To proof

As given in the question

Let us assume that the number of hours charged at the day rate = d

Let us assume that the number of hours charged at the night rate = n

An online data base charges $25 an hour during the day and $12.50 an hour at night. If a research company paid $250 for 12 hours of use.

Total working hour in a company including day and night be  12 hours .

than the equation become in the form

d + n = 12

also

An online data base charges $25 an hour during the day

$12.50 an hour at night.

If a research company paid $250 for 12 hours of use.

than the equation becomes

25d + 12.50n = 250

than the two equation are

d + n = 12 , 25d + 12.50n = 250

multiply first by 25 and subtracted  from 25d + 12.50n = 250

25d - 25d + 12.50n - 25n = 250 - 300

12.5 n = 50

n = \frac{50}{12.5}

n = 4hours

put this in the d + n = 12

d + 4 =12

d = 12-4

d = 8 hours

Therefore the number of hours charged at the day rate  is 8 hours  and at the night rate is  4hours .

Hence proved



4 0
3 years ago
Neptune’s average distance from the sun is 4.503 x 10e9 km. Mercury’s average distance from the sun is 5.791 x10e9 km.about how
Igoryamba

Answer:

77.76 times

Step-by-step explanation:

The average distance of Neptune  from the sun

= 4.503  ×  10 ⁹  k m .

and Mercury  =  5.791  ×  10 ⁷ k m .

Hence neptune is (  4.503  ×  10 ⁹) ÷ (5.791 × 10 ⁷  ) times farther from the sun than mercury

i.e.(  \frac{4.503}{5.791} )  × 10⁹⁻⁷ times

=   0.7776  ×  10 ² times

=   77.76  times.

4 0
3 years ago
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