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3 years ago

|2+3(-4)|

Mathematics

2 answers:

iragen [17]3 years ago

6 0

Answer:

Step-by-step explanation:

alrighty so the order of operations are PEMDAS (Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right)) so to start you would first multiply the 3 and the -4. you would then get |2-12| which would simply to |-10| which would then go down to 10 because everything inside those lines/brackets/sorry i forgot the technical term lol zero out except the whole number! does that make sense? :)

puteri [66]3 years ago

3 0

Answer:

Step-by-step explanation:

So we have the expression:

$|2+3(-4)|$

First, evaluate within the absolute value bars. 3 times -4 is -12. Thus:

$=|2-12|$

Now, subtract:

$=|-10|$

The absolute value of -10 is positive 10. So:

$=10$

And we're done!

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Answer:

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Step-by-step explanation

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4 years ago

Find the area under the standard normal distribution curve for the following intervals. a. Between z = 0 and z = 2.0 b. To the r

vesna_86 [32]

Answer:

a) $P(0$

And we can use the following excel code to find the probability:

"=NORM.DIST(2,0,1,TRUE)-NORM.DIST(0,0,1,TRUE)"

$P(0$

b) $P(Z>1.5) =1-P(Z$

And we can use the following code and we got:

"=1-NORM.DIST(1.5,0,1,TRUE)"

$P(Z>1.5) =1-P(Z$

c) $P(z$

And we can use the following code and we got:

"=NORM.DIST(-1.75,0,1,TRUE)"

$P(z$

d) $P(-2.78$

And we can use the following excel code to find the probability:

"=NORM.DIST(1.66,0,1,TRUE)-NORM.DIST(-2.78,0,1,TRUE)"

$P(-2.78$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Part a

We want this probability:

$P(0$

And we can use the following excel code to find the probability:

"=NORM.DIST(2,0,1,TRUE)-NORM.DIST(0,0,1,TRUE)"

$P(0$

Part b

For this case we want this probability:

$P(Z>1.5)$

And we can use the complement rule and we have:

$P(Z>1.5) =1-P(Z$

And we can use the following code and we got:

"=1-NORM.DIST(1.5,0,1,TRUE)"

$P(Z>1.5) =1-P(Z$

Part c

We want this probability:

$P(z$

And we can use the following code and we got:

"=NORM.DIST(-1.75,0,1,TRUE)"

$P(z$

Part d

We want this probability:

$P(-2.78$

And we can use the following excel code to find the probability:

"=NORM.DIST(1.66,0,1,TRUE)-NORM.DIST(-2.78,0,1,TRUE)"

$P(-2.78$

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4 years ago