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3 years ago

- The expression below shows a number in

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

3 0

B is the answer so if you want to know you can tell me if it is wrong

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Evaluate the expression x^4+9x^2 when x=-3

aalyn [17]

Answer:

162

Step-by-step explanation:

Step 1: Define

x⁴ + 9x²

x = -3

Step 2: Substitute and Evaluate

(-3)⁴ + 9(-3)²

81 + 9(9)

81 + 81

162

6 0

3 years ago

Read 2 more answers

789,091 to the nearest ten thousand

slava [35]

i think it's 790,000 or 800,000 i hope i helped

6 0

3 years ago

f(x) = 0.2^x is transformed 9 units right, compressed vertically by a factor of 1/6 and reflected across the x-axis. Write the t

postnew [5]

Answer:

The function g(x) is defined as $g(x)=-\frac{1}{6}(0.2)^{x-9}$ .

Step-by-step explanation:

The given function is

$f(x)=-(0.2)^x$

The function f(x) transformed 9 units right, compressed vertically by factor of 1/6 and reflected across the x-axis.

The transformation of function is defined as

$g(x)=kf(x+b)+c$

Where, k is vertical stretch, b is horizontal shift and c is vertical shift.

If b>0, then the graph of f(x) shifts b units left and if b>0, then the graph of f(x) shifts b units right.

If c>0, then the graph of f(x) shifts c units upward and if c>0, then the graph of f(x) shifts c units downward.

The value of b is -9 because the graph shifts 9 units right. The value of k is 1/6. If the graph of function f(x)reflect across x-axis, therefore the function is defined as -f(x).

$g(x)=\frac{1}{6}(-f(x-9))$

$g(x)=-\frac{1}{6}(0.2)^{x-9}$ $[\because f(x)=-(0.2)^x]$

Therefore the function g(x) is defined as $g(x)=-\frac{1}{6}(0.2)^{x-9}$ .

7 0

3 years ago

Read 2 more answers

I need help to solve the system of equation by elimination. x - 2y = -10 -5x + 4y = 14

Agata [3.3K]

Your answer is an ordered pair (2,6)

3 0

3 years ago

2(3/4)=5 3(4×2)=1 1/4+4/3

Andrej [43]

Answer:

$2( \frac{3}{4} )= 5 \\ \frac{3}{2} = 5 \\ 3 = 5 \times 2 \\ 3 = 10$

$3( 4 \times 2) = 1 \\ 3(8) = 1 \\ 24 = 1$

$\frac{1}{4} + \frac{4}{3} \\ \frac{1}{1} + \frac{1}{3} \\ 1 \times 3 + 1 \times 1 \\ 3 + 1 \\ 4$

3 0

2 years ago